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3 years ago

Write an equation in standard form with integer coefficients for the line with slope 14/3 going thought the point (-3,-5)

Mathematics

1 answer:

kipiarov [429]3 years ago

7 0

Y-y1=m(x-x1)
y+5=14/3* (x+3)
y+5= (14/3)x+14
y=(14/3)x+9
(14/3)x+9-y=0 /*3
14x-3y+27=0

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Step-by-step explanation:

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Answer:Solution :

{x,y,z} = {-8,52/7,-18/7}

System of Linear Equations entered :

[1] 2x + 4y + 3z = 6

[2] 5x + 8y + 6z = 4

[3] 4x + 5y + 2z = 0

Solve by Substitution :

// Solve equation [3] for the variable z

[3] 2z = -4x - 5y

[3] z = -2x - 5y/2

// Plug this in for variable z in equation [1]

[1] 2x + 4y + 3•(-2x-5y/2) = 6

[1] -4x - 7y/2 = 6

[1] -8x - 7y = 12

// Plug this in for variable z in equation [2]

[2] 5x + 8y + 6•(-2x-5y/2) = 4

[2] -7x - 7y = 4

// Solve equation [2] for the variable y

[2] 7y = -7x - 4

[2] y = -x - 4/7

// Plug this in for variable y in equation [1]

[1] -8x - 7•(-x -4/7) = 12

[1] -x = 8

// Solve equation [1] for the variable x

[1] x = - 8

// By now we know this much :

x = -8

y = -x-4/7

z = -2x-5y/2

// Use the x value to solve for y

y = -(-8)-4/7 = 52/7

// Use the x and y values to solve for z

z = -2(-8)-(5/2)(52/7) = -18/7

Solution :

{x,y,z} = {-8,52/7,-18/7}

Step-by-step explanation:

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