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Komok [63]
2 years ago
7

If a1=1. And r=1/5 find a8

Mathematics
1 answer:
Kruka [31]2 years ago
7 0

Answer:

a₈ = \frac{1}{78125}

Step-by-step explanation:

The nth term of a geometric sequence is

a_{n} = a₁(r)^{n-1}

Here a₁ = 1 and r = \frac{1}{5} , then

a₈ = 1 × (\frac{1}{5}) ^{7} = 1 × \frac{1}{78125} = \frac{1}{78125}

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Over what interval will the immediate value theorem apply
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Answer:

Any [a,b] that does NOT include the x-value 3 in it.

Either an [a,b] entirely to the left of 3, or

an  [a,b] entirely to the right of 3

Step-by-step explanation:

The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.

Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.

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3 years ago
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Hope This Helps You!
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