8 times 2 is 16 and 12 times 3 is 36. So 16 plus 36 is 52
Answer:
120 degrees
Step-by-step explanation:
interior angle of regular polygon = [ ( n − 2 ) × 180 ] / n
n = number of sides
hence, in b), n = 6
interior angle of regular polygon = [ ( 6 − 2 ) × 180 ] / 6 = 120
Answer:
y = - x + 4
Step-by-step explanation:
gradient = change in y/change in x
1-6/3--2= -5/5 = -1
y= -x + c
1=-3+c
c=4
equation of line =
y= -x + 4
Answer:
The population of the students at the University after 5 years is <u>442</u>.
Step-by-step explanation:
Given:
Current population of students is, 
Growth rate is, 
Time after which population is needed is, 
Let 'P' be the population after 't' years.
Population growth is an exponential growth and the equation to determine the population after 't' years is given as:

Now, plug in 400 for
, 0.02 for 'r', 5 for 't' and solve for 'P'. This gives,

Therefore, the population of the students at the University after 5 years is 442.
After solving the system of equations, x= -3 and y=6
Step-by-step explanation:
We need to solve the following system of equations by substitution.

Finding value of y from equation(1) and substituting it in equation(2)

The value of x is x=-3
Now, Finding value of x from eq(1) and substituting in equation(2)

So, Value of y is y=6
After solving the system of equations, x= -3 and y=6
Keywords: system of equations
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