AN elevator has a placard stating that the maximum capacity is1720lb-10passengers. So , 10 adult male passengers, find the proba
bility that it is overloaded because they have a mean weight greater than 172lb.(Assume that weights of males are normally distributed with mean of 177 lb and a standard deviation of32lb). Dose this elevator appear to be safe?
We will check if the elevator can hold 10 man X~(177,32^2) n= 10 P(SigmaX>172) SigmaX~(177*10,(32^2)*10) SigamX~N(1770, 101.19^2) P(SigmaX>172*10=1720) =Z=(1720-1770)/101.19 Z = -0.49 From Z table Z=-0.49 P(Z=-0.49) = 0.3121 (probability they will not overload) 1- 0.3123 = 0.6879 = 68.79% The elevator is not safe, the probability to be more the 172 is 68.79%, high probability they could not make it.
Step-by-step explanation: because when you have a number that has x as a variable, you cant add or subtract those numbers together when both numbers have different variables.
