Find the missing endpoint if S is the midpoint RT. R(-9, 4) and S(2, -1); Find T.

Please help for 20 points!! thank you if you help

Verizon [17]

Answer:

b

Step-by-step explanation:

3 0

2 years ago

The temperature of a certain solution is estimated by taking a large number of independent measurements and averaging them. The

Mademuasel [1]

Answer:

(a) The 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b) The confidence level is 68%.

(c) The necessary assumption is that the population is normally distributed.

(d) The 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

Step-by-step explanation:

Let X = temperature of a certain solution.

The estimated mean temperature is, $\bar x=37^{o}C$ .

The estimated standard deviation is, $s=0.1^{o}C$ .

(a)

The general form of a (1 - α)% confidence interval is:

$CI=SS\pm CV\times SD$

Here,

SS = sample statistic

CV = critical value

SD = standard deviation

It is provided that a large number of independent measurements are taken to estimate the mean and standard deviation.

Since the sample size is large use a z-confidence interval.

The critical value of z for 95% confidence interval is:

$z_{0.025}=1.96$

Compute the confidence interval as follows:

$CI=SS\pm CV\times SD\\=37\pm 1.96\times 0.1\\=37\pm0.196\\=(36.804, 37.196)\\\approx (36.80^{o}C, 37.20^{o}C)$

Thus, the 95% confidence interval for the temperature is (36.80°C, 37.20°C).

(b)

The confidence interval is, 37 ± 0.1°C.

Comparing the confidence interval with the general form:

$37\pm 0.1=SS\pm CV\times SD$

The critical value is,

CV = 1

Compute the value of P (-1 < Z < 1) as follows:

$P(-1$

The percentage of z-distribution between -1 and 1 is, 68%.

Thus, the confidence level is 68%.

(c)

The confidence interval for population mean can be constructed using either the z-interval or t-interval.

If the sample selected is small and the standard deviation is estimated from the sample, then a t-interval will be used to construct the confidence interval.

But this will be possible only if we assume that the population from which the sample is selected is Normally distributed.

Thus, the necessary assumption is that the population is normally distributed.

(d)

For n = 10 compute a 95% confidence interval for the temperature as follows:

The (1 - α)% t-confidence interval is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

The critical value of t is:

$t_{\alpha/2, (n-1)}=t_{0.025, 9}=2.262$

*Use a t-table for the critical value.

The 95% confidence interval is:

$CI=37\pm 2.262\times \frac{0.1}{\sqrt{10}}\\=37\pm 0.072\\=(36.928, 37.072)\\\approx (36.93^{o}C, 37.07^{o}C)$

Thus, the 95% confidence interval for the temperature if 10 measurements were made is (36.93°C, 37.07°C).

3 0

3 years ago

What product lies between 5x7/10=

Paraphin [41]

5/1 • 7/10=
35/10=
3 5/10=
3 1/2

5 0

3 years ago

Sherman goes golfing every 6th day and Brad goes golfing every 7th day. If Sherman and Brad both went golfing today, how many da

igor_vitrenko [27]

If they go golfing on the same day again your answer will be
42)

8 0

3 years ago

Read 2 more answers

Select the correct answer.

Nina [5.8K]

Answer:

D. $x^2 + 3x - 88$

Step-by-step explanation:

Area of rectangle = $length (l) * width (w)$

Length of rectangle = (x - 8)

Width = (x + 11)

Area of rectangle = $(x - 8)(x + 11)$

Expand the expression

$x(x + 11) -8(x + 11)$ (distributive property of multiplication)

$x^2 + 11x - 8x - 88$

Combine like terms

$x^2 + 3x - 88$

Expression for the area of the rectangle = $x^2 + 3x - 88$

7 0

3 years ago

Find the missing endpoint if S is the midpoint RT. R(-9, 4) and S(2, -1); Find T. ​

Find the missing endpoint if S is the midpoint RT. R(-9, 4) and S(2, -1); Find T.