Question

Q4.B/ Evaluate the integral

Answer 1

Answer:

answer 6

Step-by-step explanation:

It has been a long time that i have done that!

$\int\limits^3_2 {\int\limits^2_0 {(4-y^2)} \, dy} \, dx \\\\\\=\int\limits^3_0 {(4-y^2)} \, dy*(2-0)\\\\=2*[4y-\dfrac{y^3}{3} ]^3_0\\\\=2*(12-9)\\\\=6$