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lapo4ka [179]
3 years ago
6

Simplif the expression -3 ÷ (- 2/5)

Mathematics
1 answer:
kati45 [8]3 years ago
6 0

Answer:

15/2

Step-by-step explanation:

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3(x+5) - 3 = 2(3x + 1) - 3 <br> how many solutions does this equation have?
sleet_krkn [62]

Answer:

Step-by-step explanation:

1 solution: x=13/3

6 0
3 years ago
louis makes a$15 [er hour working at the mall. which equation represents the total amout of money, d, louis makes in h hours?
emmainna [20.7K]

Answer:

15H = D

Step-by-step explanation:

Given that Louis makes $ 15 per hour working at the mall, to determine which equation represents the total amout of money, D, Louis makes in H hours, the following calculation must be performed:

15H = D

So, for example, if Louis worked 10 hours, the equation would operate as follows:

15 x 10 = D

150 = D

3 0
3 years ago
How many cubes with the side lengths of 1/2 cm does it take to fill the prisim?
My name is Ann [436]

Answer:

Number of cubes that fills the prism=24

Step-by-step explanation:

The number of cube that completely fill the prism=Volume of Prism/Volume of cube with side 1/2 cm=0.5 cm

Volume of  the prism=Length*Width*Height

Length=2 cm\\\\    Width=1 cm\\   \\ Height=3/2 cm = 1.5 cm

Volume of Prism = 2*1*1.5

                      =3.0 cm^3

Volume of the Cube:

                                    Side*Side*Side\\\\=0.5*0.5*0.5

                                      = 0.125 cm^3

Number of cubes that fills the prism:

                                        3.0/0.125\\\\=24 cubes

So, the number of cubes that can fill the prism is '24'

8 0
3 years ago
Floyd is an aspiring music artist. He has a record contract that pays him a base rate of \$200$200dollar sign, 200 a month and a
Vikentia [17]
$644-$200=444
444 / 12 = 37
8 0
3 years ago
Read 2 more answers
Finding the inverse of the function x^3+3x+1 is beyond the scope of this course. Nevertheless, you should be able to use your kn
slega [8]

Step-by-step explanation:

{x}^{3}  + 3x + 1 = 1 =  =  =  >  \\  {x}^{3} + 3x = 0 =  =  =  >  \\  x({x}^{2}  + 3) = 0 \\ x = 0 \: or \\  {x}^{2}  + 3 = 0 =  =  =  >  \\  {x}^{2}  =  - 3 =  =  =  > x 1=   \sqrt{ - 3} \: or \: i \sqrt{3}   \\ x2 =  -  \sqrt{ - 3}  =  =  =  > x2 = -  i \sqrt{3}

{x}^{3}  + 3x + 1 = 5 =  =  =  >  \\  {x}^{3} + 3x - 4 =  =  =  > \\  (x - 1)( {x}^{2}   + x + 4) = 0 =  =  =  >  \\ x - 1 = 0 =  =  > x1 = 1 \\  {x}^{2}  + x + 4 = 0 =  =  =  >  \\ x2 =  - 1 + i \sqrt{3}   \\  x3 =  - 1 - i \sqrt{3}

{x}^{3}  + 3x + 1 = 3 =  =  =  >  \\{ x}^{3}  + 3x - 2 = 0 =  =  =  > x = 0.6

4 0
2 years ago
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