The options aren't given, however, the range of amount spent could be calculated
Answer:
Kindly check explanation
Step-by-step explanation:
Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amounts that could be the price of the dvd
Given that :
DVD costs the same amount
Number of DVD's = 3
Cost of cds = 10
Number of cds = 7
Total cost of cd's = 10 * 7 = 70
Let the price of DVD = x
Total amount spent = 90 - 100
Lowest price of DVD :
(amount spent - price of cd) / number of dvd
(90 - 70) / 3 = 20 /3 = 6.667
Highest price :
(100 - 70) / 3 = 30 / 3 = 10
Hence the pice of each DVD will range between /
6.6666 and 10.
Hence, prices listed within the range above are possible.
Answer:
(0, 1 ) and (
, )
Step-by-step explanation:
Given the 2 equations
x³ - xy = 0 → (1)
x + y = 1 → (2) ( subtract x from both sides )
y = 1 - x → (3)
Substitute y = 1 - x into (1)
x² - x(1 - x) = 0
x² - x + x² = 0
2x² - x = 0 ← factor out x from each term on the left side
x(2x - 1) = 0
Equate each factor to zero and solve for x
x = 0
2x - 1 = 0 ⇒ 2x = 1 ⇒ x =
Substitute these values into (3) for corresponding values of y
x = 0 : y = 1 - 0 = 1 ⇒ (0, 1 )
x = : y = 1 - = ⇒ ( , )
The expirmental probability us 28/50
Theoreticaly the probability is 25/50 because that would be half :)
Answer:
3/4
Step-by-step explanation:
Rise over run.
Go up 3 units and 4 units to the right to find the next point
