Answer:
From Online Buying is more suitable
The difference between per diaper price is $0.04
Step-by-step explanation:
Given:
56 diapers can be bought for $ 28
and
online 112 diapers for $ 52
TO find:
Better deal = ?
Per diaper save= ?
Solution:
Let the first type be x
Now for x
Price of 56 diapers are $ 28
Price of one diaper =
=$0.5 / diaper
Now for online let it be represented by O
Price of 112 diapers are $52
Price of one diaper =
=$0.46 / diaper
Price of one diaper from online is less then price of one diaper from we bought not online
Difference of per diaper price = 0.5 - 0.46
=$0.04
So buying diapers from online would be suitable
In general to be able to add or subtract fractions you need to have the same denominator so that you can add the numerators.
The easiest way to find the same denominator is to identify the lowest common denominator (LCD).
You can find the LCD by finding the prime factors of the denominators in question and multiplying them all together. If the denominators share a prime factor, only multiply it once.
Sometimes you can just eyeball the numbers to find the LCD, which might be faster.
For #W we need to find the LCD of 10 and 6, so prime factorize:
10 = 2 x 5
6 = 2 x 3
LCD = 2 x 5 x 3 = 30
The LCD is 30, so we need to change the fraction to reflect that. Remember, what you do to the denominator you need to do to the numerator as well. So:
-9/10 becomes -27/30 (both multiplied by 3)
-1/6 becomes -5/30 (both multiples by 5)
Now you can easily add:
-27/30 + (-5/30) = -32/30
In summary:
Step #1: find LCD (prime factor or eyeball)
Step #2: multiply the numerator of each fraction by the factor needed to obtain the LCD in that denominator
Step #3: add the fractions now that they have the LCD
Here’s the solution to #G:
-¾ + (-7/12)
Step #1:
4 = 2 x 2
12 = 2 x 2 x 3
LCD = 2 x 2 x 3 (count each unique prime factor once)
Step #2:
-¾ becomes -9/12 (both multiplied by 3)
-7/12 stays the same (it already has the LCD)
Step #3:
-9/12 + (-7/12) = -16/12
Let me know if you have any questions. Try to work though the others!
Answer:
Upper Control Limit for a c-chart = 9.1
Step-by-step explanation:
Given - construction company has just constructed 150 new apartments. An external inspector is hired to do the final checking before they are given way to prospective customers. Inspector at random selects 8 apartments and and counts how many defects are in each one them. He finds 7,3, 2, 1, 2, 5, 4, 4 defects.
To find - What will be Upper Control Limit for a C chart ?
Proof -
Upper Control Limit for a c-chart = c bar + 3(square root of c bar)
Now,
c bar = = 3.5
∴ we get
Upper Control Limit for a c-chart = 3.5 + 3(square root of 3.5)
= 3.5 + (1.87)
= 3.5 + 5.61
= 9.1
⇒Upper Control Limit for a c-chart = 9.1
Make a frequency table to show the following test times (in minutes) for a reading test. 81, 63, 61, 58, 72, 70, 79, 68, 82, 64,
kodGreya [7K]
Sorry about my handwriting. this is what your graph should look like