What is the standardform of R(4, 0), m = 5

Each pound of food C contains 6 ounces of ingredient P and 3 ounces of ingredient Q. Each pound of food D contains 4.5 ounces of

GuDViN [60]

So hmm the food C = 6p + 3q and the food D = 4.5p + 1.5q

now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

$\bf \textit{ratio of "p"}\implies \cfrac{6}{4.5}\implies \cfrac{4}{3}
\\\\\\
\textit{ratio of "q"}\implies \cfrac{3}{1.5}\implies \cfrac{2}{1}$

so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3

and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20

now the "p" part... ends up as $\bf \cfrac{144}{7}\cdot 4\qquad and\qquad \cfrac{144}{7}\cdot 3\implies \cfrac{576}{7}\qquad and\qquad \cfrac{432}{7}$

that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M

7 0

2 years ago

Joyce is trying to solve the equation y = x2 − 8x + 7 using the quadratic formula. She has made an error in one of the steps bel

kobusy [5.1K]

Answer:

x = 1 , 7

Step-by-step explanation:

Solution:-

- The given equation is as follows:

y = x^2 - 8x + 7

- We can solve the above equation by either making factors or by using Quadratic formula.

Factor Approach:

- Using the constant "7" at the end of the quadratic equation we will determine two integer multiples such that their additions/subtraction results in "-8".

- So the only factor of "7" are:

7 x 1 = 7

-7 x -1 = 7

- We see that addition/subtraction of first (7 , 1 ) does not results in "-8", However, the sum of ( -1 , -7 ) = -1 - 7 = -8. So the correct factors are ( -1 , -7 ). So we replace "-8x" with our factors "-1x" and "-7x":

x^2 -x -7x + 7 = 0

- Take common multiples out of pair of two terms:

x*(x-1) -7*(x-1) = 0

(x-7)*(x-1) = 0

- So we equate each term in bracket with "0" and evaluate the values of x:

(x-7) = 0 , x = 7

(x-1) = 0 , x = 1

- So the solution to the quadratic equation is:

x = 1 , 7

4 0

3 years ago

What is the equation that goes through (4,5) and is parallel to y=2x+1

forsale [732]

Answer:

The equation would be y = 2x - 3

Step-by-step explanation:

To start, we need to note that they will have the same slope, since parallel lines have the same slope. Then, we can use the point-slope form to find the equation.

y - y1 = m(x - x1)

y - 5 = 2(x - 4)

y - 5 = 2x - 8

y = 2x - 3

5 0

3 years ago

Find the area for this problem

KIM [24]

Answer:

63 for the whole figure, for the different shaded regions it goes as follows, 17.5 for the white area and 45.5 for the grey area

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

let n be a natural number such that GCF(n, 70)= 10, and LCM(n, 70)=210. Find N. (Hint: Do you remember that LCM(A,B) x GCF(A, B)

Luden [163]

The natural number , n is 30

<h3>How to determine the value</h3>

Given;

GCF(n, 70) = 10

LCM(n, 70) = 210

We have that;

LCM(A,B) x GCF(A, B)= A x B

Then,

(n, 70) = n × 70 = 70n

10 × 210 = 2100

Equate the two expressions

70n = 2100

n = $\frac{2100}{70}$

n = $30$

Thus, the natural number , n is 30

Learn more about GCF and LCM here:

brainly.com/question/640517

#SPJ1

4 0

1 year ago