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maksim [4K]
3 years ago
12

How do I do this? f(a)=4a+5; Find f(2)

Mathematics
1 answer:
Mariana [72]3 years ago
6 0
F(2)=4(2)+5
f(2)=8+5
f(2)=13
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9. The endpoints of a diameter of a circle are A (2,1) and B(5,5). Find the area of the circle in terms of . (1 point)
Georgia [21]

Answer:

Area of the circle is 6.25π sq.unit

Step-by-step explanation:

The centre of the circle is at the mid point of a diameter. Th mid point of the diameter is at (5+22,5+12)or(72,3),which is centre. Radius is the distance from end point (5,5)to centre (72,3)∴r=√(5−72)2+(5−3)2=√1.52+4=√6.25=2.5∴

Area of the circle is Ac=π⋅r2=π⋅2.52=6.25π sq.unit[Ans]

5 0
3 years ago
Read 2 more answers
Rectangle A measures 9inches by 3 inches, rectangle B is a scaled copy of rectangle A . What are all the measurements pairs that
Tanzania [10]

Answer:

Dimensions of Rectangle B will be 9x inches by 3x inches where x is a scaling factor.

Step-by-step explanation:

Scaled Copy: It means that the rectangle A is related to rectangle B by some scaling (multiplying) factor x.

As we are given Dimensions of rectangle A =  9 inches by 3 inches

Then for any scaling factor x the dimensions of rectangle B will be:

Dimensions of Rectangle B = x * ( Dimensions of rectangle A)

Dimension of rectangle B = x * (9 inches by 3 inches)

Dimensions of rectangle B = 9x inches by 3x inches

For more understanding let we assume that rectangle B is scaled copy of rectangle A by scaling factor x=3; then we will have the dimensions of rectangle B as under:

For scaling factor (x) = 3;

Dimensions of Rectangle B = x * ( Dimensions of rectangle A)

Dimensions of rectangle B = 3 (9 inches by 3 inches)

Dimensions of rectangle B = 27 inches by 9 inches

On the other hand for scaling factor x=0.75, the dimensions of rectangle B will become as under;

Dimensions of Rectangle B = x * ( Dimensions of rectangle A)

Dimensions of rectangle B = 0.75 (9 inches by 3 inches)

Dimensions of rectangle B = 6.75 inches by 2.25 inches

8 0
3 years ago
Determine the domain of the function.<br><br> f(x)=4/x^2
harkovskaia [24]
Since x can be any value as long as the denominator equals 0 (it doesn't matter if it's positive or negative), we have to figure out when x^2=0, which is when x=0. Therefore, the domain is (-inf, 0) U (0, inf) 
3 0
3 years ago
Let A = -4k+ 3 and B = 3k +17. If A = B, then what is the value of k?​
kupik [55]

Answer:

k=-2

Step-by-step explanation:

Using substitution to find what you're missing, (in this case k) is when you plug each letter into the other equation:

-4k+3=3k+17

So now solve for k:

subtract 3 from both sides...

-4k=3k+14

subtract 3k from both sides to combine with -4k...

-7k=14

divide -7 from both sides...

k=-2

3 0
2 years ago
Which is true of the multiples of a prime number
vodka [1.7K]
You can't multiply anything to get a prime number ?
6 0
3 years ago
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