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3 years ago

In algebraic expression Three-fourths the square of a number.

Mathematics

2 answers:

allsm [11]3 years ago

4 0

Answer:

3/4x^2

Step-by-step explanation:

Sauron [17]3 years ago

4 0

Answer:

$\frac{3}{4} \sqrt{x}$

where 'X' is the number

Step-by-step explanation:

hope this helps

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Suppose Cotangent (theta) = StartFraction 5 Over 12 EndFraction, where Pi less-than theta less-than StartFraction 3 pi Over 2 En

Agata [3.3K]

Answer:

Sin theta = 12/13

Step-by-step explanation:

From the question;

Cot theta = 5/12

Kindly recall;

Cot theta = 1/ tan theta

Hence, tan theta = 12/5

Mathematically

tan theta= opposite/adjacent

to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides

let hypotenuse be h

h^2 = 12^2 + 5^2

h^2 = 144 + 25

h^2 = 169

h = √169

h = 13

But sine theta = opposite/ hypotenuse = 12/13

5 0

3 years ago

Find the GCF of the list below.<br> - 20x^3y. 4x^4 y^2. 60x^4y

iogann1982 [59]

Answer:

Check photo

Step-by-step explanation:

8 0

3 years ago

Help me pls pls pls pls

Alex Ar [27]

5 2/4 because 3 and 2 are 5 and 1/4 plus 1/2 make up 2/4 meaning its either 5 2/4 or 5 1/2

now i get brainly <3

6 0

2 years ago

Which could be the first step and simplifying this expression? Check all that apply.

Triss [41]

$\bf \left( x^3x^{-6} \right)^2\implies \left( x^{3-6} \right)^2\implies \stackrel{1st~Step}{\left( x^{-3} \right)^2}\implies x^{-6}\implies \cfrac{1}{x^6}\\ \qquad \Downarrow\\ \stackrel{\textit{distributing the exponent}}{\left( x^{3\cdot 2}x^{-6\cdot 2} \right)}\\ \qquad \Downarrow\\ \stackrel{1st~Step}{x^6x^{-12}}\\ \qquad \Downarrow\\ x^{6-12}\\ \qquad \Downarrow\\ x^{-6}\\ \qquad \Downarrow\\ \cfrac{1}{x^6}$

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3 years ago

Log(1+y) - log(1-y) = log x in 2 decimal places, express y in terms of x

GaryK [48]

Answer: $y = \frac{x-1}{x+1}$

Step-by-step explanation:

$log(1+y) - log(1-y) = log x \\log\frac{1+y}{1-y} =log x\\x = \frac{1+y}{1-y}\\x(1-y)=1+y\\x-xy=1+y\\x-1 = xy+y\\y(x+1)=x-1\\y=\frac{x-1}{x+1}$

6 0

3 years ago

Read 2 more answers