1) which of the following statements is true about U.S. Rule?

1 answer:

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1) --
2) --
3) 175,900 / 12.5% = 1,407,200 CHOICE B.
4) SUPPLIES
5) PURCHASES
6) 5,000 + 21,800 - 790 - 5,100 = 20,910 CHOICE D.
7) D. 50%
8) C. UNITS OF PRODUCTION
9) B. INCOME STATEMENT
10) A.) 6,480
11) D.) MULTIPLIED BY BOOK VALUE AT THE BEGINNING OF THE YEAR.

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PLEASE HELP ASAP! Will give brainliest if you explain

Romashka-Z-Leto [24]

Well, the best way to solve this would involve the Pythagorean theorem.
First, take the length of the hypotenuse (the string in this case) and square it. Do the same to the side length we are given (the kites height above the ground).
We then subtract the squared height from the squared hypotenuse. We should be left with 1,781m.
All we have to do now is find the square root of 1,781m.

Your answer for b is 42.20189569m.

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3 years ago

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What is the answer to that problem?

Rom4ik [11]

It will take him 182 because when you divide 2175 by12 u get 181.25 and you have to add a day for the point .25

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3 years ago

If a man goes to a cafe he wants to buy a wrap with the price of 8.80 dollars he gives the cafe lady 10 dollars how much change

Tomtit [17]

It would be $1.20
8.80 + 1.20 = 10

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2 years ago

Line passing through (2,5) and the m= -5/6

kiruha [24]

Answer:

y - 5 = (-5/6)(x - 2)

y - 5 = (-5/6)x + 10/6

y - 30/6 = (-5/6)x + 10/6

y = (-5/6)x + 20/3

Step-by-step explanation:

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2 years ago

What is the kinetic Energy of a 110 kg linebacker rushing towards his football

Leviafan [203]

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

$KE=\frac{1}{2} \times m v^{2}$

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

$K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules$

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2 years ago