The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.
<h3>What are the steps of this construction?</h3>
1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.
2. Without altering it, with the aid of the compass, do draw an art above and also below the said line segment from one of the segment endpoints.
3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.
4. Then do draw the point of intersection that is said to exist between the pair of arts below the line segment and also in-between the pair of arts as seen below the line segment
5. Lastly, do make use of a straight edge to link the intersection points between the both pair of arts.
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Answer:
The surface area for this cylinder is 252*pi square inches.
Step-by-step explanation:
The surface area of a cylinder can be calculated by using the following formula:
surface area = 2*pi*r² + 2*pi*r*h
Applying the data from the problem, we have:
surface area = 2*pi*(6)² + 2*pi*(6)*15
surface area = 2*pi*36 + 180*pi
surface area = 72*pi + 180*pi
surface area = 252*pi
The surface area for this cylinder is 252*pi square inches.
The complete question is as follows:
Jessica is a custodian at Oracle Arena. She waxes 20
of the floor in
of and hour. At this rate, how many square meters can she wax per hour
?
Answer:

Step-by-step explanation:




Answer:
D
Step-by-step explanation:
15 + 2x + x + 3 = 3x + 18
hope this helps
Answer:
182 children, 91 adults, 60 students
Step-by-step explanation:
The quantity of adults is x, then the quantity of children are 2x, the quantity of students is 333-x-2x=333-3x. The charge from all adults is 12x, students gave 7*(333-3x), children gave 5*2x=10x, the sum of all money is 2422
12x+ 7(333-3x)+10x=2422
12x+2331-21x+10x=2422
2331+x=2422
x=91- the amount of adults
1) 91*2=182- the amount of children
333-91-182= 60- the amount of students