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Zinaida [17]
2 years ago
11

4n² + 3n +5 and 2n²+3​

Mathematics
1 answer:
joja [24]2 years ago
6 0

Answer:

6n^2+3n+8

Step-by-step explanation:

simplify like terms. keep the exponent the same degree it started as

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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
Simpify the expression. -2(y + 3) -7y
jenyasd209 [6]
-2y-6-7y
-9y-6
I hope that this helps!
4 0
2 years ago
After 4,000 gallons of water were added to a large water tank that was already filled to 3/4 of its capacity, the tank was then
dangina [55]

Answer:  The correct option is

(E) 80,000.

Step-by-step explanation:  Given that after adding 4,000 gallons of water to a large tank that was already filled to \dfrac{3}{4} of its capacity, the tank was then at \drac{4}{5} of its capacity.

We are to find the number of gallons of water that the tank hold when filled to capacity.

Let the tank can hold x gallons of water when filled to capacity.

Then, according to the given information, we have

\dfrac{3}{4}x+4000=\dfrac{4}{5}x\\\\\\\Rightarrow \dfrac{4}{5}x-\dfrac{3}{4}x=4000\\\\\\\Rightarrow \dfrac{16-15}{20}x=4000\\\\\Rightarrow x=4000\times20\\\\\Rightarrow x=80000.

Thus, the required capacity of the tank is 80,000 gallons of water.

Option (E) is CORRECT.

4 0
3 years ago
Please help ASAP don’t mind the scribbles
hjlf

U = 1

L = 0

R = -2

I = 24

M = 17

H = -3

E = 100

S = -439

O = 11

B = -6

T = -41

D = 19

C = 206

<em>Hope this helped ! :)</em>

8 0
3 years ago
Simplify <br><br> 3m^-2<br> over <br> 5n^-3
aivan3 [116]
<span>3m^-2           3n^3
---------    =  -----------
5n^-3            5m^2

hope it helps</span>
8 0
2 years ago
Read 2 more answers
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