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2 years ago

11

4n² + 3n +5 and 2n²+3

1 answer:

joja [24]2 years ago

6 0

Answer:

6n^2+3n+8

Step-by-step explanation:

simplify like terms. keep the exponent the same degree it started as

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Katalin drove 300 miles on her vacation. She drove an average of 1.9 times faster on the second 150 miles of her trip than she d

viktelen [127]

300=x+1.9x
I got this by dividing the problem into two parts x[the speed of the first half] plus 1.9x [the speed of the second half increased by 1.9] both of those together should give you 300.
I went further and solved this...If you placed 103.5 into this problem for x you should get 300.15!

8 0

2 years ago

To solve a problem, a student had to find a certain angle θ. The student got to the

stira [4]

Answer:

see explanation

Step-by-step explanation:

sinΘ is only valid for values in the interval

- 1 ≤ Θ ≤ 1

sinΘ = $\frac{5}{2}$ is outwith this interval and is not valid

3 0

2 years ago

Karen earns $54.60 for working 6 hours. If the amount she earns varies directly with the

Andrei [34K]

Given:

Karen earns $54.60 for working 6 hours.

Amount she earns varies directly with the number of hours she works.

She need to work to earn an additional $260.

To find:

Number of hours she need to work to earn an additional $260.

Solution:

Let the amount of earnings be A and number of hours be t.

According to question,

$A\propto t$

$A=kt$ ...(i)

where, k is constant of proportionality.

Karen earns $54.60 for working 6 hours.

$54.60=k(6)$

Divide both sides by 6.

$\dfrac{54.60}{6}=k$

$9.1=k$

Put k=9.1 in (i).

$A=9.1t$

Substitute A=260 in the above equation.

$260=9.1t$

Divide both sides by 9.1.

$\dfrac{260}{9.1}=t$

$28.5714=t$

$t\approx 29$

Therefore, she need to work extra about 29 hours to earn an additional $260.

3 0

2 years ago

Each of 28 students in Romi’s class raised at least $25 during jump-a-thin. What is the least amount of money the class raised

Anna [14]

28 x 25 = $700

Answer: The class raises at least $700.

3 0

2 years ago

Read 2 more answers

2 different companies offer online subscriptions. Company A charges $75 upfront and $20 per month. Company B does not charge the

ki77a [65]

Answer:

$15$ months

Step-by-step explanation:

Given that company $A$ charges $\$75$ upfront and $\$20$ per month and company B does not charge the upfront fee but charges $\$35$ per month.

Let after $n$ months both the company charges the same amount.

Total charges by the company $A=\$ (75+n\times 20)$ and total charges by the company $B=\$ (n\times 35)$ .

Now, from the given condition both the charges are equal, so

$75+n\times 20=n\times 35 \\\Rightarrow 75= 35 n - 20 n\\\Rightarrow 75= 15 n \\\Rightarrow n= \frac {75}{5} \\\Rightarrow n= 15$

Hence, after $15$ months both the company charges the same amount.

4 0

2 years ago