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choli [55]
3 years ago
10

Pls can anyone mention pri.e numbers from 1 to 100..

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0
<h2><em><u>2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97</u></em></h2>

hope it will help you Mark me as brilliant

tankabanditka [31]3 years ago
3 0

Answer:

hope this helps and you meant prime numbers

Step-by-step explanation:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97

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3 years ago
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3 years ago
Find the dimensions of a rectangle with perimeter 116 m whose area is as large as possible. (if both values are the same number,
creativ13 [48]
The dimensions would be 29 by 29.

To maximize area and minimize perimeter, we make the dimensions as close to equilateral as possible.  

Dividing the perimeter by the number of sides, we have

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This means that both length and width can be 29.
5 0
4 years ago
5700 is compounded semiannually at a rate of 15% for 12 years
Rama09 [41]

Answer:

$32,335.38

Step-by-step explanation:

You are going to want to use the compound interest formula, which is shown below.

P(1+\frac{r}{n} )^{nt}

<em>P = initial balance </em>

<em>r = interest rate </em>

<em>n = number of times compounded annually </em>

<em>t = time</em>

<em />

Now lets plug in the values into the equation:

5,700(1+\frac{.15}{2})^{12(2)} = 32,335.38

Your answer is $32,335.38

4 0
3 years ago
Please help im doing my girl friend work and i dont know not a thing
Nadusha1986 [10]

Answer:

See below, please!

Step-by-step explanation:

We can set up a system of equations to model this problem. Let's consider the student's ticket as x, and y for the adult ticket.

So since the student ticket is $1.50, and adult is $4, we can set up the following equation: 1.5x+4y=5050, since they collected $5050 total.

We can set up another equation modeling the number of people who came to the game. This would be x+y=2200.

Solve this, and we get x= 1500 and y=700. So, they sold 1500 student tickets and 700 adult tickets.

Hope this helped!

4 0
3 years ago
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