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Arlecino [84]
3 years ago
11

The distance an object falls varies directly as the square of the number of seconds it falls. If an object falls 256 feet in 4 s

econds, how far will it fall in 6 seconds.
Mathematics
2 answers:
azamat3 years ago
5 0

Answer:

576 feet

Step-by-step explanation:

D = kt²

256 = k(4)²

16k = 256

k = 16

D = 16t²

D = 16(6)²

D = 16 × 36

D = 576

Kryger [21]3 years ago
4 0

Answer:

384 ft

Step-by-step explanation:

d₁ = kₓt₁²

256 = kₓ4

k = 256/4 = 64

d₂ = kₓt₂² = 64ₓ6 = 384 ft

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Anna [14]
<span>Given the function d(h)=50+45 represents the distance a family traveled, in miles, h hours after they stopped for lunch. The value 45 represents the speed they are traveling in miles per hour. So if the function will be graph, the 45 represents the slope of the line.</span>

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5 0
3 years ago
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The function f(x)= 1000(2)^x where x is the number of weeks, represents the cicada population on a farm. Use a function to answe
bulgar [2K]
The y intercept is where the line crosses the y axis or where x=0
basically f(0) which is 1000 or B


the y intercept is when x=0, when time=0, so it represents the amount of cicadas initially on the farm


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7 0
3 years ago
Water is pumped from a tank at constant rate, and no more water enters the tank. If the tank contains 19140 L at 4:47 PM and 809
Sladkaya [172]

Answer:

The liters that the tank will contain at 5:11 PM that day are:

  • <u>4416 Liters</u>.

Step-by-step explanation:

Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:

  • 19,140 L - 8,097 L = 11,043 L

And the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:

  • Outlet flow = \frac{Volume}{Time}
  • Outlet flow = \frac{11,043 L}{18 min}
  • Outlet flow = 613.5 \frac{L}{min}

Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:

  • Outlet flow = \frac{Volume}{Time}
  • Volume = Outlet flow * time

And replace the values to obtain the new volume pumped:

  • Volume = 613.5 \frac{L}{min} * 6 min
  • Volume = 3681 L.

At last, you must subtract these liters from the last volume identified in the tank:

  • New Volume in the tank = 8097 L - 3681 L
  • New Volume in the tank = 4416 L

The volume in the tank at 5:11 PM is <u>4416 Liters</u>.

5 0
3 years ago
The scale factor of the blueprint of a wall to the actual wall is 0.07. The area of the actual wall is 36ft² what is the area of
ss7ja [257]

Answer:

The area of the wall on the blueprint is 0.1764 ft²

Step-by-step explanation:

The scale is the relationship that exists between the magnitudes of a drawing and the actual dimensions.

The scale factor is the ratio of the dimensions in two similar figures. The term "similar figures" refers to figures that have the same shape but different sizes.

 The ratio between areas is equal to the squared scale factor. This is,  the scale factor for areas is the squared scale factor,

To solve scale problems in this case, then the following proportion must be proposed:

\frac{representation area}{actual area} =scale factor^{2}

Being:

  • representation area=?
  • actual area=36 ft²
  • scale factor=0.07

Replacing:

\frac{representation area}{36 ft^{2} } =0.07^{2}

Solving:

representation area= 0.07²*36 ft²

representation area=0.1764 ft²

<u><em>The area of the wall on the blueprint is 0.1764 ft²</em></u>

4 0
4 years ago
Please can someone explain me this
Inga [223]

Answer:

blackness?

Step-by-step explanation:

8 0
3 years ago
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