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2 years ago

Write the first 10 multiples of 2 and 3 and find LCM.

Mathematics

1 answer:

schepotkina [342]2 years ago

6 0

Answer:

multiples of 2 2,4,6,8,10,12,14,16,18,20

multiples of 3 3,6,9,12,15,,18,21,24,27,30

Step-by-step explanation:

Lcm is 6

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Find the formula for the area of the shaded region in the figure.<br> x² = 4py<br> ہے

Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

$A=\frac{8}{3} \sqrt{p h} \cdot h$

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

$\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\$

Generally, the equation for the Area is mathematically given as

$& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\$

$&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h$

$A=\frac{8}{3} \sqrt{p h} \cdot h$

In conclusion, the equation for the Area is

$A=\frac{8}{3} \sqrt{p h} \cdot h$

Read more about Area

brainly.com/question/27683633

#SPJ1

5 0

1 year ago

4. What is the rule of the nth term of the geometric sequence with <img src="https://tex.z-dn.net/?f=a_%7B4%7D" id="TexFormula1"

hram777 [196]

Answer:

$\text{d.}\quad a_n=-2.25(2)^{n-1}$

Step-by-step explanation:

The common ratio is given as 2, so the base of any exponential must be 2 (not -2 or 2.25). The 4th term is negative, so the initial value must be negative (since the multiplying factor is positive). The only selection matching these requirements is d.

You know the general term is ...

... an = a1·r^(n-1)

so the 4th term is

... -18 = a1·2^(4-1) = 8·a1

Then the first term is ...

... a1 = -18/8 = -2.25 . . . . . confirms our choice of answer d.

7 0

2 years ago

A prairie dog left its burrow 5 feet underground and started digging deeper into the ground. It digs straight down at a constant

SpyIntel [72]

Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.

Initially, the dog is 5 feet underground.

Each minute, the dog goes 2 more feet underground.

Hence, the underground height of the dog after t seconds is given by:

$h(t) = 5 + 2t$

The time it takes for the dog to reach 13 feet underground is <u>t for which h(t) = 13</u>, hence:

$h(t) = 5 + 2t$

$13 = 5 + 2t$

$2t = 8$

$t = \frac{8}{2}$

$t = 4$

It takes 4 min for the prairie dog to reach 13 feet underground.

A similar problem is given at brainly.com/question/25290003

7 0

2 years ago

Can someone please help me?

Oliga [24]

1/36 because you have 36 different possibilities when rolling it twice and getting and a 4 then a 6 is only 1 possibility out of the 36
1/4 because there is 3/6 chance on one roll and second roll
We said with 2 rolls there is 36 possibility (6x6)
So 3x3=9 which the amount of possibility to get a even number
9/36 simplify is 1/4 (divided by 9 the top and bottom)
Hope this helps!
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6 0

2 years ago

Read 2 more answers

What is wrong with this solution

zzz [600]

Answer:

A. -5m/5 does not equal m

Step-by-step explanation:

-5m/5 = -m, not m.

In step 2, both sides should be divided by -5, not by 5.

Answer: A. -5m/5 does not equal m

7 0

2 years ago

Write the first 10 multiples of 2 and 3 and find LCM.​

Write the first 10 multiples of 2 and 3 and find LCM.