Answer:
4/5
Step-by-step explanation:
we divide by 3 the numerator and the denominator:
(12/3) / (15/3)
we have:
4/5
The simulation of the medicine and the bowler hat are illustrations of probability
- The probability that the medicine is effective on at least two is 0.767
- The probability that the medicine is effective on none is 0
- The probability that the bowler hits a headpin 4 out of 5 times is 0.3281
<h3>The probability that the medicine is effective on at least two</h3>
From the question,
- Numbers 1 to 7 represents the medicine being effective
- 0, 8 and 9 represents the medicine not being effective
From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two
So, the probability is:
p = 23/30
p = 0.767
Hence, the probability that the medicine is effective on at least two is 0.767
<h3>The probability that the medicine is effective on none</h3>
From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none
So, the probability is:
p = 0/30
p = 0
Hence, the probability that the medicine is effective on none is 0
<h3>The probability a bowler hits a headpin</h3>
The probability of hitting a headpin is:
p = 90%
The probability a bowler hits a headpin 4 out of 5 times is:
P(x) = nCx * p^x * (1 - p)^(n - x)
So, we have:
P(4) = 5C4 * (90%)^4 * (1 - 90%)^1
P(4) = 0.3281
Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281
Read more about probabilities at:
brainly.com/question/25870256
Answer:
P(2): 1/5
P(4): 1/5
P(odd number): 3/5
P(whole number): 5/5
P(6): 0/5
P(2 or 3): 2/5
Step-by-step explanation:
There are 5 <em>equal </em>sections in this circle. So, the probability to land in each section is 1/5.
The odd numbers are 1, 3, and 5. Since each section is 1/5, you add
1/5 + 1/5 + 1/5 = 3/5. That is the probability that you will land in any odd number.
Because all the numbers listed are whole numbers, no matter where the spinner lands it will be a whole number. So, the probability is 5/5 for whole numbers.
Since 6 is not a section, it's probability will be 0/5 (or you can just put 0).
"Or" means you add the two probabilities. Add the probability of landing on 3 (which is 1/5) to the probability of landing on 2 (which is also 1/5). So, you get 2/5.
Answer:
Step-by-step explanation:
The expected value for a discrete variable is calculated as:
Where 
and 
are the values that the variable can take and 
and 
are their respective probabilities.
So, a player can win 2 dollars or looses 1 dollar, it means that is equal to 2 and is equal to -1.
Then, we need to calculated the probability that the player win 2 dollars and the probability that the player loses 1 dollar.
If there are n identical and independent events with a probability p of success and a probability (1-p) of fail, the probability that a events from the n are success are equal to:
Where 
So, in this case, n is number of times that the player tosses a die and p is the probability to get a 6. n is equal to 6 and p is equal to 1/6.
Therefore, the probability that a player get at least two times number 6, is calculated as:
On the other hand, the probability that a player don't get at least two times number 6, is calculated as:
Finally, the expected value of the amount that the player wins is:
It means that he can expect to loses 0.2101 dollars.
