Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
The answer is 100,000
<span>In order to answer this, you must got to the number in the hundred thousand spot, in this case 1, and the check the number next to it. If it is 5 or more, the number becomes bigger, and if it is less than 5, you keep the number the same. After this, any numbers to the right become zeros. </span>
For question 1
x^7
for question 2
h^9
Answer:
B. 4 3/8
Step-by-step explanation:
7/8 X 5 = 4 3/8
Answer:
c
Step-by-step explanation:
45:15=3:1 not 1:3
