0.78 converted to a percent would be 78%
This is a combination problem. The approach to this is by using the nCr method, where n is the number of total objects and r is the number of success. For example, if you want to get 3 red out of the total 4, then that would be 4C3. That means,
4C3 = 4!/3!(4 - 3)! = 4 ways
If you want to get 2 green out of the total 6, then that would be 6C2. That means,
6C2 = 6!/2!(6-2)! = 15 ways
Therefore, there are a total of 4+15 = <em>19 ways</em>.
Answer:
Step-by-step explanation:
It is useful to remember the ratios between the side lengths of these special triangles.
30°-60°-90° ⇒ 1 : √3 : 2
45°-45°-90° ⇒ 1 : 1 : √2
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h is the shortest side, and the given length is the intermediate side. This means ...
h/1 = 2/√3
h = 2/√3 = (2/3)√3 . . . . . . simplify, rationalize the denominator
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b is the longest side, and the given length is the short side. This means ...
b/√2 = 3/1
b = 3√2 . . . . . multiply by √2
We are given that the insect can lift 1.182 x 10^3 times
it's own weight. Say that w is weight, so the lift is:
lift = 1.182 x 10^3 * w
Assuming that your body weight is 60 kg, therefore you
can lift:
lift = 1.182 x 10^3 * 60 kg = 70,920 kg
Answer:
(A) -3 ≤ x ≤ 1
Step-by-step explanation:
The given function is presented as follows;
h(x) = x² - 1
From the given function, the coefficient of the quadratic term is positive, and therefore, the function is U shaped and has a minimum value, with the slope on the interval to the left of <em>h</em> having a negative rate of change;
The minimum value of h(x) is found as follows;
At the minimum of h(x), h'(x) = d(h(x)/dx = d(x² - 1)/dx = 2·x = 0
∴ x = 0/2 = 0 at the minimum
Therefore, the function is symmetrical about the point where x = 0
The average rate of change over an interval is given by the change in 'y' and x-values over the end-point in the interval, which is the slope of a straight line drawn between the points
The average rate of change will be negative where the y-value of the left boundary of the interval is higher than the y-value of the right boundary of the interval, such that the line formed by joining the endpoints of the interval slope downwards from left to right
The distance from the x-value of left boundary of the interval that would have a negative slope from x = 0 will be more than the distance of the x-value of the right boundary of the interval
Therefore, the interval over which <em>h</em> has a negative rate of change is -3 ≤ x ≤ 1