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Inessa05 [86]
3 years ago
5

What is the value of the expression iº xixi ? x 13 x 147

Mathematics
1 answer:
icang [17]3 years ago
4 0

Answer:

2^4 = (2 x 2) x (2 x 2) = 4 x 4 = 16

Step-by-step explanation:

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Tell whether the function shown by the table below is linear or nonlinear.
Ugo [173]
I pretty sure it’s a linear function
6 0
3 years ago
What is the value of minus 6 x cubed minus y squared minus 3 x y if if x = -2 and y = 4
Oksi-84 [34.3K]

Well, "minus 6 x cubed minus y squared minus 3 x y" translates to:

-6x^{2} -y^{2} -3xy

Then, if we insert the values for x and y, we get:

-6(-2)^{2} -(4)^{2} -3(-2)(4)

When we distribute and multiply:

144-16-24

And once we combine like terms:

104<em> is the answer</em>


8 0
3 years ago
Read 2 more answers
Can someone help me ASAP!!
Lana71 [14]

The answer is 5.

Step-by-step explanation:

To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.

6 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
Solve for x. x+2/3=−1/6
Sphinxa [80]

Answer:-

x=-5/2

Step-by-step explanation:

x+2/3=-1/6

after cross-mutiplying,

6(x+2)=-3

6x+12=-3

6x=-3-12

6x=-15

x=-15/6

x=-5/2

hope this helps u!!

6 0
3 years ago
Read 2 more answers
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