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Given:
The focus of the parabola is at (6,-4).
Directrix at y=-7.
To find:
The equation of the parabola.
Solution:
The general equation of a parabola is:
...(i)
Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.
The focus of the parabola is at (6,-4).
On comparing both sides, we get
...(ii)
Directrix at y=-7. So,
...(iii)
Adding (ii) and (iii), we get
Putting in (ii), we get
Putting 
in (i), we get
Therefore, the equation of the parabola is .
Find : Which statements are always true regarding the triangle
m∠5 + m∠3 = m∠1
m∠3 + m∠4 + m∠5 = 180°
m∠5 + m∠6 =180°
m∠2 + m∠3 = m∠6
m∠2 + m∠3 + m∠5 = 180°
Solution:
External angle of triangle = Sum of opposite interior angles
m∠1 = m ∠3 + m∠5
m∠4 = m ∠2 + m∠5
m∠6 = m ∠2 + m∠3
Answer:
While x = -7 and y = 4, x² - 3xy = 133.
Step-by-step explanation:
x² - 3xy
Substitute variables.
(-7)² - 3(-7)(4)
Square -7 remembering that (-x)² = x².
49 - 3(-7)(4)
Multiply -7 and 4.
49 - 3(-28)
Multiply -3 and -28.
49 + 84
Add 49 and 84.
133
Answer:
x = 7
Step-by-step explanation:
QY = 5x
YZ = 18
QZ = 53
Thus:
QY + YZ = QZ (segment addition postulate)
5x + 18 = 53
5x = 53 - 18 (subtraction property of equality)
5x = 35
Divide both sides by 5
x = 7
