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3 years ago

Find the number 17% of which is 27 more than 14% of it.

Mathematics

1 answer:

Kay [80]3 years ago

5 0

The original number would be 900

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there is an invitation fee to join the pine river country club, as well as monthly dues. the total cost after 7 months membershi

Bumek [7]

1.5 year is also 17 months. so 4060-3125=935 which equals 10 months, then 935÷10=93.5 which gives us the monthly dues. Then 93.5×7=654.5 which gives us the total of monthly dues for 7 months without the intuition fee. Then 3125-654.5=2470.5 that gives us the intuition fee.

4 0

3 years ago

An angle measures 28° more than the measure of its complementary angle. What is the measure of each angle?

navik [9.2K]

Answer:

62°

Step-by-step explanation:

Complementary angles by definition are two or more angles that add up to 90°. So we must do 90°-62° to get the missing angle which is 62°.

Hope that helped.

7 0

4 years ago

WILL MARK BRAINLIEST HELP ASAP ASAP

Mrac [35]

Answer:

not possible

Step-by-step explanation:

8 0

3 years ago

Help with proofs please

alexandr402 [8]

Answer:

D. Subtraction Property of Equality

Step-by-step explanation:

Hope it helps.

8 0

2 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

3 years ago