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Elanso [62]
3 years ago
6

1) Define onto function. 2) Find k if f.f(k) = 5 where f (k) = 2k – 1​

Mathematics
2 answers:
luda_lava [24]3 years ago
5 0

Answer:

3

Step-by-step explanation:

2k-1=5

>2k=5+1=6

>k=3

Mama L [17]3 years ago
3 0

Answer:

1)

An onto function is a function where it's range is the term in that function.

{ \sf{if \: function \: is \: x \: to \: y}} \\ { \sf{then \: range \: of \: function \: is \: y}} \\ i.e \:  \: f(x) = y

It is given by formula:

{ \boxed{ \sf{ {x}^{y} -  {}^{x} c _{1}(n - 1) {}^{y}  +  {}^{x} c _{2} (x - 2) {}^{y} + ..... {x}^{n}   }}}

2).

f(k) = 2k - 1 \\ but \: f(k) = 5 \\ 2k - 1 = 5 \\ 2k = 1 + 5 \\ 2k = 6 \\ k = 3

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