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zloy xaker [14]
3 years ago
12

During the performance of the simple staining procedure, you failed to heat fix your E-coli smear preparation. Upon microscopic

examination , how would you expect this slide to differ from the correctly prepared slides ?
Biology
1 answer:
nikklg [1K]3 years ago
6 0

OMG I'm a business study Student so I really don't know about this stuff

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You perform a co-transduction experiment with pro+ gal+ arg- man- donor and pro- gal- arg+ man+ recipient. On master plate 1, yo
vladimir2022 [97]

Answer:

arg---pro---gal---man.

Explanation:

The co transduction frequency is directly proportional to the distance between two genes.

The recombination frequency can be calculated as follows;

A - B = (A - B / A ) x 100

Here, A and B represent the different genes.

For plate 1 :

Pro- gal = A - B = (1000 - 400/1000) x 100 = 60% . Here, A is Pro and B is gal.

Pro - Arg = A - C = (1000- 290/1000) x 100 = 71% . Here, C is Arg.

Pro - Man = A - D = (1000-1000/1000) x 100 = 0%. Here D is Man.

For Gal transductants of plate 2

Gal - Pro = A - B = (1000 - 390/1000) x 100 = 61% . Here A is Gal and B is Pro.

Gal - Arg = A - C = (1000- 289/1000) x 100 = 71% .  Here, C is Arg.

Gal - Man = A - D = (1000-900/1000) x 100 = 10%. Here D is Man.

From the recombination frequencies it is clear that the location of genes are in the order of

Thus, the correct answer is option (B).

3 0
3 years ago
2. Which would contain more water molecules?:
rosijanka [135]
The beaker containing the hot water.
6 0
3 years ago
A forest food web is shown in the picture below. How can producers be identified in this food web
dmitriy555 [2]

Answer: the answer is A, producers are any organism below the top consumers

Explanation:

its the most obvious answer there is and producers give the consumers energy and what ever eats them, its just acycle

5 0
3 years ago
The sum of michael's tidal volume, inspiratory reserve volume, and expiratory reserve volume is called his ______. the sum of mi
aliina [53]
The correct answer is vital capacity (VC).  
<span>
Vital capacity is the full amount of air that the lungs can expel after having been filled to maximum. It can be a measure of a person’s respiratory health and is usually measured regular spirometer.</span>
6 0
3 years ago
Biology lab 14 experiment 1 punnett square crosses post lab questions
djverab [1.8K]

Complete question: PUNNETT SQUARE CROSSES

1. Set up and complete Punnett squares for these crosses (remember Y = yellow, y = blue):

a. YY and Yy

b. YY and yy

2. Answer these questions: a. What are the resulting phenotypes? b. Are there any blue kernels? c. How can you tell whether or not there are blue kernels?

3. Set up and complete a Punnett square for a cross of two of the F1 from Step 1 (above).

4. Answer these questions: a. What are the genotypes of the F2 generation? b. What are their phenotypes? c. Are there more or fewer blue kernels than in the F1 generation?

5. Identify the four possible gametes produced by the following individuals (S = smooth, s = wrinkled):

a. YY Ss

b. Yy Ss

Punnett squares are used to get the genotypic and phenotypic frequencies among the progeny produced from a cross. Punnett squares and answers below.

<h3>What is a punnett square?</h3>

The Punnett square is a graphic representation that shows the different types of gamete combinations according to the alleles involved in a cross.

Punnett square shows the probabilities of getting offspring with different genotypes and their consequent phenotypes.

In the exposed example,

Diallelic genes that codes for color

Y = yellow ⇒ dominant allele

y = blue ⇒ recessive allele

We will assume complete dominance, meaning that genotypes with at least one dominant allele will express yellow.

1)

a- Cross 1

Parentals)   YY   x    Yy

Gametes) Y   Y      Y   y

Punnett square)      Y        Y

                       Y     YY      YY

                        y     Yy      Yy

F1) Genotype

1/2 = 50% of the progeny is expected to be h0m0zyg0us dominant, YY

1/2 = 50% of the progeny is expected to be heter0zyg0us, Yy

   Phenotype

100% of the progeny is expected to be yellow.

b- Cross 2

Parentals)  YY   x    yy

Gametes) Y     Y     y    y

Punnett square)      Y        Y

                       y     Yy     Yy

                        y    Yy      Yy

F1) Genotype

100% of the progeny is expected to be heter0zyg0us, Yy

   Phenotype

100% of the progeny is expected to be yellow.

2)

a. What are the resulting phenotypes? Only yellow kernels

b. Are there any blue kernels? No

c. How can you tell whether or not there are blue kernels?

Blue is the recessive phenotype for kernels. Assuming complete dominance, since all genotypes are expected to carry at least one dominant allele, all the F1 kernels are yellow.  

3) Let us cross two heter0zyg0us individuals from the F1

Parentals)  Yy   x    Yy

Gametes) Y    y     Y    y

Punnett square)     Y        y

                       Y    YY     Yy

                        y    Yy      yy

F1) Genotype

1/4 = 25% of the progeny is expected to be h0m0zyg0us dominant, YY

1/2 = 50% of the progeny is expected to be heter0zyg0us, Yy

1/4 = 25% of the progeny is expected to be h0m0zyg0us recessive, yy    

   Phenotype

75% of the progeny is expected to be yellow.

25% of the progeny is expected to be blue.

4)

a. What are the genotypes of the F2 generation?

- 25% YY (h0m0zyg0us dominant)

- 50% Yy (Heter0zyg0us)

- 25% yy (H0m0zyg0us recessive)

b. What are their phenotypes?

- 75% yellow kernels

- 25% blue kernels

c. Are there more or fewer blue kernels than in the F1 generation?

More. Blue kernels appeared in the F2.

5. Assuming independent genes, the resulting gametes after meiosis are as follows

                        Gametes

a. YY Ss   ⇒   YS, YS, Ys, Ys

b. Yy Ss  ⇒     YS, Ys, yS, ys

You can learn more about punnett squares at

brainly.com/question/25357981

#SPJ1

7 0
2 years ago
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