Answer:

Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean
kilograms and standard deviation
kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and 
And the best way to solve this problem is using the normal standard distribution and the z score given by:

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:

So then the corresponding z scale would be:

Answer:
1500ft
Step-by-step explanation:
Ight so 60/12 is 5. So then you'd multiply 100 by 5 to get 500, therefore she is moving 500 yards per minute.
Then you'd obviously just convert that to feet which is 1500 feet.
In a right rectangle, we have:


For your exercice, hypotenuse=12
The exercise also inform the angle 60°, then:

Answer:
A) Yes, 7
Step-by-step explanation:
The given sequence An = {13, 20, 27, 34, ...}
Here the first term Ao = 13 and difference between the successive terms is (d) = 7
That is d = 20 - 13
d = 7
It is an arithmetic sequence. d = 7
Answer: Yes, it is arithmetic sequence and common difference (d) = 7
Thank you.
Answer:
-2
Step-by-step explanation:
Subtracting a negative number is the same as adding it, so this is basically just negative 8 plus 6, which is -2. Don't know who was right though, you kinda left that part of the question out.