where is the question to this
The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.
Step-by-step explanation:
The given is,
The sum of two numbers is 21
The second number is six times the first number
Step:1
Let, m - First number
n - Second number
Step:2
From given,
n - 6m ( The second number is six times the first number )
Equation becomes,
Sum = m + n
Where,
21 = m + ( 6m )
21 = 7m
m = 3
Substitute m value n becomes,
n = 6m
= (6 × 3)
n = 18
Result:
The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.
You can cut it in 4 pieces
Answer:
issolat variable
subtract constant
individualize variable
divide by coeficient
answer
Step-by-step explanation:
