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stiv31 [10]
2 years ago
12

A new car is purchased for 19000 dollars. The value of the car depreciates at 11.25% per year. What will the value of the car be

, to the nearest cent after 14 years?
Mathematics
2 answers:
bagirrra123 [75]2 years ago
8 0

Answer: 3573.64

Step-by-step explanation:

Exponential Functions:

y = ab^{x}

a=starting value = 19000

r=rate = 11.25%=0.1125

Exponential Decay:

b=1-r=1-0.1125=0.8875

Write Exponential Function:

y=19000(0.8875)^x

Plug in time for x:

y=19000(0.8875)^14

y= 3573.6388855

Evaluate :

y=3573.64

Doss [256]2 years ago
3 0

Answer: 11.25% depriciation means 11.25% amount decrases per year.

i.e for 1year (1-0.1125)19000=0.8875*19000

so for 14 years multiply 0.08875 14 times to 19000.

Your answer will be arrived.

If any doubt comment.

Step-by-step explanation:

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AlexFokin [52]

Answer: 1,2 and 4

Step-by-step explanation:

factors of 12 are :  1,2,3,4,6,12

factors of 28 are :1,2,4,7,14,28

commom  factors are= 1,2,4

8 0
2 years ago
Help me find the answer please
elena-s [515]

Answer:

60

Step-by-step explanation:

m∠1=(55+65)/2=60

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2 years ago
The base of a triangle exceeds the height by 9 centimeters. If the area is 56 square centimeters, find the length of the base an
shepuryov [24]

Answer:

The height of the triangle is 7cm and the base is 16cm

Step-by-step explanation:

First of all we have to know the formula to calculate area of ​​a triangle

a = area = 56

b = base

h = heigth

a = (b * h)/2

we replace the known values and we make 2 equations

56cm² = (b * h)/2

b = h + 9cm

we replace b by (h + 9cm) in the first equation

56cm² = (h + 9cm * h)/2

56cm² * 2 = h² + 9h

0 = h² + 9h - 112cm²

we use bhaskara formula:

(-b (±) √ (b² - 4ac) ) / 2a

we replace with the known values

h = (-9 (±) √ (9² - 4*1*(-112) ) ) / 2*1

h = (-9 (±) √ (81 + 448) ) ) / 2

h = (-9 (±) √529) /2

h = (-9 (±) 23)/2

h1 = (-9 + 23) / 2

h1 = 14 / 2

h1 = 7

h2 = (-9 - 23) / 2

h2 = -32 / 2

h2 = -16

The height of the triangle is 7cm and the base is 16cm

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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7 0
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Read 2 more answers
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
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