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3 years ago

deandre downloaded 8 apps onto his tablet in 12 secs at this rate how many apps could he download in one minute

1 answer:

7 0

Because 1 minute is 60 seconds, and it takes 12 seconds to download 8 apps, the first thing we need to do is find out how many "sets" of 12 seconds can go in 60 seconds:

60 / 12 = 5

Now, all we have to do is multiply the number of apps by 5, and we get our answer:

8 · 5 = 40

So, it would take Deandre 1 minute to download 40 apps.

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The triangle below are drawn on 1-cm dot paper. find the perimeter of each triangle

AnnyKZ [126]

There is no triangle below. Try to edit this problem.

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3 years ago

What is the solution of 3/x+8 =-4? Ox= -72 O x= -66 O x = 58 O no solution

castortr0y [4]

Answer:

There is no solution the answers there is not the right answer

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3 years ago

Alycia created a personal budget for the upcoming month. She received a salary of $2,700 and had various fixed and variable expe

Luda [366]

Answer:

C. 32%

Step-by-step explanation:

First, you have to determine the amount they spent on entertainment and food:

Salary $2,700

Taxes: 10%: $270

Fixed expenses: $1,161

Savings: $405

$2,700-$270-$1,161-$405= $864

Alycia spent $864 on entertainment and food. Now, you have to find the percent of her income that this amount represents:

($864/$2,700)*100= 32%

According to this, the answer is that the percent of her income that was spent on entertainment and food is 32%.

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3 years ago

joyville has a population of 20,750 people. its population is increasing at a rate of 2.9% each year. what is the function?

harina [27]

Answer:

Step-by-step explanation:

Since the rate is greater than 1 this is an exponential growth function of thr form

y=ar^x, where y=final value, a=initial value, r=common ratio or rate, and x=term number

In this case a=20750, r=1.029 so

y=20750(1.029)^x

3 0

3 years ago

8. Let R be the relation on the set of all sets of real numbers such that SRT if and only if S and T have the same cardinality.

sergejj [24]

Answer:

We must prove that the relation is reflexive, symmetric and transitive. Recall that to sets have the same cardinality if there exist a bijective mapping between them.

Reflexive: Take the identity map $I:S\rightarrow S$ , which is bijective. Then SRS.

Symmetric: If SRT then, there exist a bijective map $f:S\rightarrow R$ . In order to prove that TRS just take the inverse map of $f$ : $f^{-1}$ which is also bijective. Therefore, TRS.

Transitivity: Suppose that SRT and TRU. Also, assume that $f$ is the bijective map between S and T, and $g$ the bijective map between T and U. It is not difficult to check that the map $h=g(f)$ is bijective and $h:S\rightarrow U$ . Therefore, SRU.

Hence, the relation R is an equivalence relation.

The equivalence class of the set {0,1,2} is the class of all the sets with three elements, and we can associate it with the number 3. There is a construction of natural numbers based on this idea.

The equivalence class of Z is the same equivalence class of N. Therefore, is the class of all denumerable or countable sets.

Step-by-step explanation:

When we want to prove that a given relation R is equivalence, we need to check that R satisfies all the three conditions: reflexive, symmetric and transitivity. Usually the first two are very simple to prove and comes directly from the definition. The transitivity is more tricky. In this case we need to recall the definition of cardinality.

7 0

3 years ago