Don't give me the answer just explain where I messed up.

Mathematics

2 answers:

ira [324]3 years ago

7 0

Answer:

9x^2 -2x+8

Step-by-step explanation:

( 9x^2 -5x) - ( -3x -8)

Distribute the minus sign

( 9x^2 -5x) +3x +8

Combine like terms

9x^2 -2x+8

The x^2 should be positive and you have it as negative

givi [52]3 years ago

6 0

Answer:

Their is not supposed to be a negative sign infront of the 9x

Step-by-step explanation:

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Based upon a smaller sample of only 170 st. paulites, what is the probability that the sample proportion will be within of the p

Pepsi [2]

Given that in 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hired by the Better Business Bureau to investigate the complaints they received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is .75, the same as the overall proportion of complaints settled in 2008.

Part a) :

Suppose you select a sample of 450 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

Population proportion = 0.75
sample size. n = 450
$Standard\ error=\sqrt{\frac{p(1-p)}{n}} \\ \\ =\sqrt{\frac{(0.75)(0.25)}{450}} = 0.0204$

Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0204.

Part b) :

Based upon a sample of 450 complaints, what is the probability that the sample proportion will be within .04 of the population proportion (to 4 decimals)?

The probability that the sample proportion will be within 0.04 of the population proportion is given by:

$P(p\ \textless \ 0.75\pm0.04)=2P\left(z\ \textless \ \frac{0.04}{0.0204} \right)-1 \\ \\ 2P(z\ \textless \ 1.961)-1=2(0.97505)-1=1.9501-1 \\ \\ =\bold{0.9501}$

Therefore, the probability that the sample proportion will be within .04 of the population proportion is 0.9501.

Part C:

Suppose you select a sample of 200 complaints involving new car dealers. Show the sampling distribution of (to 4 decimals).

Population proportion = 0.75
sample size. n = 200
$Standard\ error=\sqrt{\frac{p(1-p)}{n}} \\ \\ =\sqrt{\frac{(0.75)(0.25)}{200}} = 0.0306$

Therefore, the sampling distribution has a proportion of 0.75 and a standard error of 0.0306.

Part D):

Based upon the smaller sample of only 200 complaints, what is the probability that the sample proportion will be within .04 of the population proportion (to 4 decimals)?


The probability that the sample proportion will be within 0.04 of the population proportion is given by:

$P(p\
 \textless \ 0.75\pm0.04)=2P\left(z\ \textless \ \frac{0.04}{0.0306} 
\right)-1 \\ \\ 2P(z\ \textless \ 1.306)-1=2(0.90429)-1=1.80858-1 \\ \\
 =\bold{0.8086}$

Therefore, the probability that the sample proportion will be within .04 of the population proportion is 0.8086.

8 0

3 years ago

I need a answer to 77.5% of 13.270

den301095 [7]

Answer:

10.28425

Step-by-step explanation:

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