Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
Since there are 16 ounces in 1 pound. You'd multiply 450(pounds)*16(ounces) which would equal 7,200 ounces.
Hope this helped : )
28 to 42 means 28/42
We now reduce 28/42 to lowest terms.
28 ÷ 7 = 4
42 ÷ 7 = 6
We now have 4/6.
We now reduce 4/6.
4 ÷ 2 = 2
6 ÷ 2 = 3
Final answer: 2/3
Answer:
8cm and 2cm
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