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2 years ago

a recipe which yields 5 serving calls for 2 cups of milk. how many cups of milk are needed to make 9 servings?

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

3 0

Answer:

3.6 cups of milk

Step-by-step explanation:

Create a proportion where x is the number of cups of milk needed for 9 servings:

$\frac{5}{2}$ = $\frac{9}{x}$

Cross multiply and solve for x:

5x = 18

x = 3.6

So, 3.6 cups of milk are needed to make 9 servings.

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2x^(2) + xy + 2y^(2) = 5, (1, 1) (ellipse)

Anvisha [2.4K]

2x2+xy+2y2=5Implicit differentiation yields4x+y+xy′+4y y′=0Solve for y′.

answer is- y = 4x+ y /5x

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3 years ago

What is 7,259 rounder to the nearest thousand?

Paul [167]

The answer will be 7300

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3 years ago

A number is picked randomly in the range [2,8]. If past selection indicates that the numbers picked are less than 5, what is the

yawa3891 [41]

Answer:

a) P = 2/7

b) P = 4/7

c) P = 1/7

Step-by-step explanation:

In the range of [2,8], we have the following integers which are: 2, 3, 4, 5, 6, 7, 8. So this is a total of 7 integers.

a) We look for the probability that the numbers are less than 4, so we conclude that there are possible numbers 2 and 3 out of possible 7, so the required probability is equal to P = 2/7.

b) We look for the probability that the numbers are greater than 4, so we conclude that there are possible numbers 5, 6, 7, 8 out of possible 7, so the required probability is equal to P = 4/7.

c) Based on the previous two examples, we conclude that the required probability is P = 2/7· 1/2=1/7.

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3 years ago

A cell phone tower covers a circular area with a radius of 15 miles. You are at a location that is 11 miles west and 12 miles so

Murljashka [212]

Answer:

No you do not.

This is because we can use Pythagoras Theorem to show that our location sits outside the 15 mile radius of the cell tower.

To work is out you would write the equation

${11}^{2} + {12}^{2} = 265$

Then to work out the Hypotheses you would

$\sqrt{265} = 16.2788205961$

Which proves that the location is outside of the 15 Mile radius of the cell tower.

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3 years ago

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 40.6 + 0.42 = 41.02$ cm

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

3 0

3 years ago