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Alex Ar [27]
3 years ago
7

Round 0.139 to the nearest tenth.

Mathematics
2 answers:
Savatey [412]3 years ago
5 0

Answer:

0.1

Step-by-step explanation:

1-4 you keep the number the same and 5-9 you go up once.

tenth=0.1

hundredth=0.03

thousandth=0.009

since the hundredth is 3, you would keep the number the same

storchak [24]3 years ago
3 0

Answer:

0.1

Step-by-step explanation:

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In one minute,kayla can read 142 words.if she keeps this same rate, how many words can she read in 1 hour ???show your work
Anon25 [30]

Answer:

8,760

Step-by-step explanation:

If Kaylah is reading 142 words in one minute, there is 60 minutes in an hour.

therefore,

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8 0
4 years ago
Read 2 more answers
I’m not sure how to do this please help
Nikolay [14]

Answer:

B :step 2   she didnt collect all the like terms and calculate

Step-by-step explanation:

first rewrite  remove all (  )Parentheses

2nd   collect all like terms and calculate

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3 years ago
Combine like terms and simplify 4r - 6 - 2r + 5
murzikaleks [220]
C. 10r-3


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4 0
3 years ago
Question 5: prove that it’s =0
mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that \cos(\frac{2}{x}) is a variable number between -1 and 1 (inclusive).

This means that -1 \le \cos(\frac{2}{x}) \le 1.

x^4 \ge 0 for all value x. So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

By squeeze theorem, if  -x^4 \le x^4 \cos(\frac{2}{x}) \le x^4

and \lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L, then we can also conclude that \im_{x \rightarrow} x^4\cos(\frac{2}{x})=L.

So we can actually evaluate the "if" limits pretty easily since both are continuous  and exist at x=0.

\lim_{x \rightarrow 0}x^4=0^4=0

\lim_{x \rightarrow 0}-x^4=-0^4=-0=0.

We can finally conclude that \lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0 by squeeze theorem.

Some people call this sandwich theorem.

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3 years ago
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Mrrafil [7]

Answer:I want to go to school

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