Comment.
9A
Let's use (a) as an example. What number is in front of the x inside be brackets? If I gave you the choice of 1,2,3,4,5 which number is it out of those 5?
If you chose 5, you have the second best answer. You are reading outside the brackets. Not what we need.
If you choose 1, you are well on your way. There is a 1 beside the x.
Now go to the outside of the brackets. What's in front of the x? 1,2,3,4,5.. There is only one number you can choose. It's a 5. So the result outside the brackets is 5x. How did 1x become 5x? You had to put a 5 on the blank to the left of the brackets..
5(5 + x) = 5x + ___ What goes on the line to the right of 5x? Rule whatever you do to one side of a plus sign inside the brackets, you must do to the other side of the plus sign.
It becomes 5*5
So the blank is filled with 25. And here's the answer.
5(5 + x) = 5x + 25 <<<< answer..
Stop don't do anything more. 5x and 25 are not like terms. They don't mix
9B
Let's make this one brief so that you have something to do. What did you multiply 5 by to get 10? You should answer 2.
2(x + 5) = ___ x + 10
What you do on one side of the plus sign, you must do on the other. So what's in front of the x on the right?
2(x + 5) = 2x + 10 <<<< answer
Step-by-step explanation:
B 1 solution should be correct but i don’t really know
Answer:
2(7) - 1/4 = 4 + 1/3x
x = 117/4
Step-by-step explanation:
solving an equation with one missing variable
step 1: multiply 2 * 7
ex: 14 - 1/4 = 4 + 1/3x
step 2: subtract 14 from 1/4
ex: 55/4 = 4 + 1/3x
step 3: subtract 4 from both sides of the equation
55/4 - 4 = 4 + 1/3x - 4 (39/4 = 1/3x)
step 4: divide both sides of the equation by 1/3
ex: 39/4 / 1/3 = 1/3x / 1/3 (x = 117/4 or x = 29 1/4)
step 5: to check your answer add the answer you got from the last equation which was 117/4 or 29 1/4 and input it into the original equation and get your final answer
ex: 2(7) - 1/4 = 4 + 1/3(117/4)
14 - 1/4 = 4 + 39/4
55/4 = 55/4 (if both sides of the equation are the same numbers like 55/4 = 55/4 then your answer is true)
Let's go through these, sentence by sentence:
a. <em>Henry is driving at a constant speed.</em>
If the y-axis represents the speed of Henry's car, this portion of the graph should be a straight horizontal line, as his speed doesn't change at all. This already eliminates the first and second options.
<em>He then slows down to pass an accident. After passing it, he goes back to his original speed and continues driving at that speed</em>.
We should see a downward-sloped line segment during the period when he slows down, and then an upward-sloped line segment during the time where he speeds up. Graphically, this would look like a V. Finally, the graph would again become a straight horizontal line as he returned to and maintained his original speed. Graph #4 is the only one which represents this description.
b. <em>Teresa is driving to work. She drives at a constant speed for several miles, then stops to pick up breakfast</em>.
On all of the graphs of this situation, the y-axis represents Teresa's <em>distance to work</em>. We have to be careful here, because the further she drives, <em>the further down the graph goes</em>. The y-coordinate starts at some positive fixed position (the total distance to work) and works its way down to 0.
There's only one graph which represents this scenario - a downwards trend - and that's graph #3.
