Yes
7.539 is greater than 7.344 by 0.195
hope this helps
Answer:
At 95% confidence level, the confidence interval that is likely to contain the percent,
, of all teenagers at the wheel when an accident occurred is given as follows;
12.7% <
< 18.6%
Step-by-step explanation:
The parameters given are as follows;
Sample size, n = 582
Proportion of accidents where teenagers are at the wheel,
= 15.6%
x = 0.156*582 ≈ 91
The formula for the confidence interval is as follows;
![CI=\hat{p}\pm z\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=CI%3D%5Chat%7Bp%7D%5Cpm%20z%5Ctimes%20%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
Where:
z = z value at the confidence level
We therefore have;
![CI=0.156\pm z\times \sqrt{\dfrac{0.156(1-0.156)}{582}}](https://tex.z-dn.net/?f=CI%3D0.156%5Cpm%20z%5Ctimes%20%5Csqrt%7B%5Cdfrac%7B0.156%281-0.156%29%7D%7B582%7D%7D)
![CI=0.156\pm z\times 1.504 \times 10^{-2}](https://tex.z-dn.net/?f=CI%3D0.156%5Cpm%20z%5Ctimes%201.504%20%5Ctimes%2010%5E%7B-2%7D)
At a confidence level of 95%, z = 1.96
The confidence interval at 95% confidence level is therefore;
12.7% <
< 18.6%.
Answer:
30%
Step-by-step explanation:
Regualar price= £50
New price= £65
Find the increase- £65- £50 = £15
Change % =
×100= 30%
The increase in 30%
Answer:
A
Explanation
8/11 = 8 ÷ 11
<u>B</u><u>R</u><u>A</u><u>I</u><u>N</u><u>L</u><u>I</u><u>E</u><u>S</u><u>T</u><u> </u><u>P</u><u>L</u><u>E</u><u>A</u><u>S</u><u>E</u>