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2 years ago

I own the collector’s edition of my favorite Pokemon card. It used to be worth $120 USD. Now it is worth $150 USD.

Mathematics

1 answer:

qaws [65]2 years ago

6 0

Answer:

By 25%

Step-by-step explanation:

150-120=30 30/120=1/4 1/4=25%

Check:

120x.25=30 30+120=150

Hope this helps

Whats ur favortie pokemon? (:

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3 years ago

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A minor-league hockey team had the following scores for the start of the season: 3, 6, 2, 1, 2, 3, 0, 4, 5, 1, 5, 4.

ale4655 [162]

If the hockey team scores 9 goals in their next game, it means that; the mean would be the most affected.

<h3>How to find mean, median and mode?</h3>

We are given the data set as;

3, 6, 2, 1, 2, 3, 0, 4, 5, 1, 5, 4.

Let us rearrange in ascending order to get;

0, 1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6.

The mean = (0 + 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6)/12 = 3

Median = (3 + 3)/2 = 3

Mode = 1, 2, 3, 3, 5

Now, if they score 9 goals in their next game, it means that;

Mean = 45/13 = 3.46

Median = 3

Mode remains the same

Thus, mean will be the most affected.

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2 years ago

Approximately 85% of electronic stores marked up the price for a new headset. Suppose a random sample of 12 stores is selected.

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Answer:djdjdjxbc. D

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2 years ago

Find the face value of the 20-year zero-coupon bond at 4.4%, compounded semiannually, with a price of $8,375.

umka21 [38]

<u>Given</u>:

Time,

t = 20 years

Rate,

r = 4.4%

Price

= $8,375

Now,

The yield will be:

= $\frac{4.4}{2}$

= $1.1$ (%)

Time will be:

= $20\times 2$

= $40 \ periods$

As we know the formula,

⇒ $Price \ of \ bond = \frac{Face \ value}{(1+\frac{r}{2} )^{n\times 2}}$

By substituting the values, we get

$8375=\frac{Face \ value}{(1+\frac{0.044}{2} )^{20\times 2}}$

$8375=\frac{Face \ value}{(1.022)^{40}}$

$8375=\frac{Face \ value}{2.3880083}$

The face value will be:

$Face \ value = 2.3880083\times 8375$

$=20,000$ ($)

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3 years ago

Can someone help me with this please?

natima [27]

150/250! Hope this helps :D

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3 years ago