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2 years ago

Please someone help me I will mark you has brainiest

Mathematics

2 answers:

Anna35 [415]2 years ago

5 0

Answer:

i angle EFB

ii BFC and AFC

Step-by-step explanation:

AlexFokin [52]2 years ago

3 0

Answer:

i .angle AFC

iiAFC and AFB

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5) Choose the inequality that will help solve the following situation: A jet ski rental charges a flat rate of $75, plus an addi

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22.5

Step-by-step explanation:

You time 75 by 60. Then, you divided it by 200. The answer is 22.5.

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I h(x)is the inverse of f (x)what is the value of h (f (x))

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Answer:

h(f(x)) = x

Step-by-step explanation:

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6 0

2 years ago

Help plz find the equation

tatiyna

Question # 1

Step-by-step Explanation:

Given

$\frac{1}{2}\div \frac{2}{3}$

solving

$\frac{1}{2}\div \frac{2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{1}{2}\times \frac{3}{2}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{1\times \:3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:1\times \:3=3$

$=\frac{3}{2\times \:2}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:2=4$

$=\frac{3}{4}$

Therefore, completing the blanks:

$\frac{1}{2}\div \frac{2}{3}=\frac{1}{2}\times \frac{3}{2}=\frac{3}{4}$

Question # 3

Step-by-step Explanation:

Given

$\frac{2}{5}\div \frac{3}{4}$

solving

$\frac{2}{5}\div \frac{3}{4}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2}{5}\times \frac{4}{3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2\times \:4}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:4=8$

$=\frac{8}{5\times \:3}$

$\mathrm{Multiply\:the\:numbers:}\:5\times \:3=15$

$=\frac{8}{15}$

Therefore, completing the blanks:

$\frac{2}{5}\div \frac{3}{4}=\frac{2}{5}\times \:\frac{4}{3}=\frac{8}{15}$

Question # 5

Step-by-step Explanation:

Given

$\frac{3}{4}\div \frac{5}{7}$

solving

$\frac{3}{4}\div \frac{5}{7}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{3}{4}\times \frac{7}{5}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{3\times \:7}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:3\times \:7=21$

$=\frac{21}{4\times \:5}$

$\mathrm{Multiply\:the\:numbers:}\:4\times \:5=20$

$=\frac{21}{20}$

Therefore, completing the blanks:

$\frac{3}{4}\div \frac{5}{7}=\frac{3}{4}\times \:\frac{7}{5}=\frac{21}{20}$

6 0

2 years ago

What are the coordinates of the endpoints of the midsegment for △DEF that is parallel to DE¯¯¯¯¯?

Readme [11.4K]

Answer:

The endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

Step-by-step explanation:

If a line connecting the midpoint of two sides and parallel to the third side of the triangle, then it is called a midsegment.

From the given figure it is noticed that the vertices of the triangle are D(1,4), E(1,1) and F(-3,3).

If the midsegment is parallel to DE, then the end points of the midsegment are mid point of DF and EF.

Midpoint formula.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Midpoint of DF,

$Midpoint=(\frac{1-3}{2},\frac{4+3}{2})$

$Midpoint=(-1,3.5)$

Midpoint of EF,

$Midpoint=(\frac{1-3}{2},\frac{1+3}{2})$

$Midpoint=(-1,2)$

Therefore the endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).

3 0

2 years ago

Please someone help me I will mark you has brainiest​

Please someone help me I will mark you has brainiest