Question

10. Find four consecutive integers such that the sum of the first three is one more than twice the largest.

Answer 1

Answer:

2,3,4,5

Step-by-step explanation:

let four consecutive numbers are x,x+1,x+2,x+3

condition:

x+(x+1)+(x+2)+1=2(x+3)

3x+4=2x+6

3x-2x=6-4

x=2

Now first number 2

2nd number=x+1

2nd number=2+1=3

3rd number=x+2

3rd number=2+2=4

4th number=x+3

4th number=2+3=5