C=√a²+b. square both sides
c²=a²+b². subtract a² from both sides
c²-a² = b². take the square root of both sides
b=±√c²-a²

but since length can never be negative we consider only the positive root
b=√c²- a²

7 0

3 years ago

Please hurry it’s timed

frutty [35]

Answer:

I believe it is Option 1

Step-by-step explanation:

Since the fourth root of 81 will be 3 and of 16 will be 2.

4 0

3 years ago

In the coordinate plane, the directed line segment from K to N has endpoints at K(–6, –2) and N(8, 3). Point L partitions the di

KatRina [158]

The answer is C man I just took the assignment

8 0

4 years ago

Read 2 more answers

The proportion of traffic fatalities resulting from drivers with high alcohol blood levels in 1982 was approximately normally di

SSSSS [86.1K]

Answer:

a) The proportion of states would you expect to have more than 65% of their traffic fatalities from drunk driving is 0.59518.

b) The 25th percentile of this distribution is a 0.5231 proportion of deaths due to drunk driving.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.

In this problem, we have that:

Mean 0.569 and standard deviation 0.068. So $\mu = 0.569, \sigma = 0.068$

a. What proportion of states would you expect to have more than 65% of their traffic fatali- ties from drunk driving?

This is the value of X when Z has a pvalue of 0.65.

Z has a pvalue of 0.65 between $Z = 0.38$ and $Z = 0.39$ . So, we use $Z = 0.385$

$Z = \frac{X - \mu}{\sigma}$

$0.385 = \frac{X - 0.569}{0.068}$

$X - 0.569 = 0.068*0.385$

$X = 0.59518$

The proportion of states would you expect to have more than 65% of their traffic fatalities from drunk driving is 0.59518.

b. What proportion of deaths due to drunk driving would you expect to be at the 25th percentile of this distribution?

This is the value of X when Z has a pvalue of 0.25.

Z has a pvalue of 0.65 between $Z = -0.67$ and $Z = -0.68$ . So, we use $Z = -0.675$

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 0.569}{0.068}$

$X - 0.569 = 0.068*(-0.675)$

$X = 0.5231$

The 25th percentile of this distribution is a 0.5231 proportion of deaths due to drunk driving.

3 0

3 years ago