We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Answer:
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Answer:
Step-by-step explanation:
Use the Law of Cosines to find the measure of angle A from the lengths of the sides.
A = arccos[(b²+c²-a²)/(2bc)] ≅ 29.9°
B = arccos[(a²+c²-b²)/(2ac)] ≅ 54.8°
C = 180 - A - B = 95.3°
Answer:
52 sq un
Step-by-step explanation:
I'm glad to hear that, but where is the math problem?
