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Ede4ka [16]
3 years ago
6

What is the factored from of 9x^2-64

Mathematics
2 answers:
svetlana [45]3 years ago
7 0

Answer:

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) where a=3x and b=8

.

(3x+8)(3x−8)

Step-by-step explanation:

Nataly [62]3 years ago
7 0

Assignment: \bold{Factor \ Equation: \ 9x^2-64}

<><><><><><><>

Answer: \boxed{\bold{\left(3x+8\right)\left(3x-8\right)}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Rewrite \bold{9x^2-64}

\bold{\left(3x\right)^2-8^2}

[ Step Two ] Rewrite Equation

\bold{\left(3x\right)^2-8^2}

[ Step Three ] Apply Difference Of Two Squares Formula

Note: \bold{Difference \ Of \ Two \ Squares \ Formula: \ x^2-y^2=\left(x+y\right)\left(x-y\right)}

\bold{\left(3x\right)^2-8^2=\left(3x+8\right)\left(3x-8\right)}

<><><><><><><>

\bold{\left(3x+8\right)\left(3x-8\right)}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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