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Viktor [21]
3 years ago
11

17. In a speech class, students must give a final speech for their exam. The speech can be 15 minutes, or within that time by 4

minutes. Write an absolute value equation that represents the minimum and maximum lengths of the final speech ​
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

| t − 15 | = 4

Step-by-step explanation:

absolute value is weird and i see no use for it

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3/5 with an exponent of 4
nordsb [41]

Step-by-step explanation:

\text{If is}\ \dfrac{3}{5}^4,\ \text{then}\ \dfrac{3}{5}^4=\dfrac{3\cdot3\cdot3\cdot3}{5}=\dfrac{81}{5}=16\dfrac{1}{5}\\\\\text{If is}\ \left(\dfrac{3}{5}\right)^4=\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)\left(\dfrac{3}{5}\right)=\dfrac{3\cdot3\cdot3\cdot3}{5\cdot5\cdot5\cdot5}=\dfrac{81}{625}

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ehidna [41]
4 minutes
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plz mark me brinlest anwaser if you can :)
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Both sets of values have an average of 13. Is Set A's standard deviation smaller, larger, or about the same as Set B's? (Note: T
Softa [21]

Answer:

  Set A's standard deviation is larger than Set B's

Step-by-step explanation:

Standard deviation is a measure of variation. One way to judge the value of standard deviation is by looking at the range of the data. In general, a dataset with a smaller range will have a smaller standard deviation.

The range of data Set A is 25-1 = 24.

The range of data Set B is 18-8 = 10.

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The standard deviation is the root of the mean of the squares of the differences from the mean. In Set A, the differences are ±12, ±11, ±10. In Set B, the differences are ±5, ±3, ±1. We don't actually need to compute the RMS difference to see that it is larger for Set A.

Set A's standard deviation is larger than Set B's.

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