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Viktor [21]
3 years ago
11

17. In a speech class, students must give a final speech for their exam. The speech can be 15 minutes, or within that time by 4

minutes. Write an absolute value equation that represents the minimum and maximum lengths of the final speech ​
Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Answer:

| t − 15 | = 4

Step-by-step explanation:

absolute value is weird and i see no use for it

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The answer to your question is C
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Choose the correct equation for the line shown on the graph?
fomenos

<u>Answer:</u>

y=-1/4x-1

<u>How to find the </u><u>slope</u>

To find the slope of the line you need to do the change in y/change in x. This is also known as the rise/run. To do this you count the spaces in between the two points.

In this graph the change in y (rise) is 2. The change in x (run) is 8. Since the line is going down they are negative. The rise/run is -2/8. This can be simplified to -1/4.

Slope: -1/4x

<u>How to find the y-intercept</u>

To find the y-intercept, you need to look at where the line crosses y.

In this graph the line crosses y at -1.

Y-intercept: -1

<u>Final</u><u> </u><u>equation</u><u>:</u><u> </u><u>-</u><u>1</u><u>/</u><u>4x-1</u>

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2 years ago
What is the nearest hundredth of 2.6666
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2.66

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5 0
3 years ago
A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

7 0
3 years ago
I need help with this please
Y_Kistochka [10]

Answer: A. -5/4

Step-by-step explanation:

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