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Alla [95]
3 years ago
13

Theresa’s computer at home has 1 terabyte of storage. How many more bits of storage does her computer have than the combined bit

s available on her family’s phones, tablets, and cloud storage? Type your answer in scientific notation.
Mathematics
1 answer:
posledela3 years ago
3 0

Answer:

Not enough information provided

Step-by-step explanation:

To find the difference between one terabyte and the storage available to the other mediums, we would need to know the storage available to those mediums.  They can all have potentially different amounts of storage space, so we have no way to answer that part of the question.

We can however find out how many bits her computer has.  There are two lines of thought  to follow though.  kilo, mega, giga etc each generally note a multiple of 1000 in common terms.  In computer tech though, the number 1024, or 2¹⁰, is often used instead.

Starting with the layman's powers of 10, a terabyte is a thousand gigabytes, which in turn is a thousand megabytes, which is a thousand kilobytes, which is a thousand bytes.

That means that a terabyte stores 1 × 10¹² bytes.  A byte however is eight bits, giving us 8 × 10¹² bits.

Using the nerdier powers of 2 then, a byte is eight bits, so we'll call that 2³.  We then go up by multiples of 2¹⁰.  With the same logic above, a terabyte is 2¹⁰ gigabytes, which is 2¹⁰ megabytes, which is 2¹⁰ kilobytes, which is 2¹⁰ bytes.  Adding the exponents up, then a terabyte would be 2⁴³ bits

So depending on whether you use the powers of ten or powers of 2 conventions, then a terabyte is either 8 × 10¹² bits, or 2⁴³ bits.

If you want to express the latter as a power of ten for proper scientific notation, then it would be 8.796093022208 × 10¹² - a rather useless way of expressing it, but just to cover all bases.

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7. Solve the equation using the quadratic formula.<br> 3x^2 = 2(2x+1)
suter [353]

Answer:

\rm x = \dfrac{2+\sqrt{10}}{3},\dfrac{2-\sqrt{10}}{3}

Step-by-step explanation:

A quadratic equation is given to us and we need to solve the equation using the quadratic formula . The given equation is ,

\rm\implies 3x^2=2(2x+1)

Open the brackets in RHS ,

\rm\implies 3x^2= 4x + 2

Transpose all the terms to LHS ,

\rm\implies 3x^2-4x-2=0

The general form of a quadratic equation is ax² + bx + c = 0 , and the roots of the equation by the Quadratic Formula ( Shreedhacharya's Formula ) is given by ,

\rm\implies\red{ x =\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}}

Using the quadratic formula , we have ,

\rm\implies x =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(3)(-2) }}{2(3)}

Simplify ,

\rm\implies x =\dfrac{4 \pm \sqrt{16+24 }}{6}

\rm\implies x = \dfrac{4\pm \sqrt{40}}{6}

\rm\implies x =\dfrac{4\pm 2\sqrt{10}}{6}

\rm\implies\boxed{\pink{\frak{ x = \dfrac{2+\sqrt{10}}{3},\dfrac{2-\sqrt{10}}{3}}}}

8 0
3 years ago
What is the answer of this when was the indipendence day
Paladinen [302]

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6 0
3 years ago
2) Which two statements are not true?
GalinKa [24]

Answer:

A repeating decimal is not a rational number and The product of two irrational numbers is always rational

Step-by-step explanation:

One statement that is not true is "The product of two irrational numbers is always rational". Take for example the irrational numbers √2 and √3. Their product is √6 which is also irrational.

The other false statement is "A repeating decimal is not a rational number". Take for example the repeating decimal 0.33333..... It can be written as 1/3 which is a rational number.

3 0
3 years ago
1. |4n-15|=|n|<br> 2. |2c+8|=|10c| <br> can you please show the work for both
Alja [10]

Problem 1

<h3>Answers: n = 3 or n = 5</h3>

---------------

Work Shown:

|4n - 15| = |n|\\\\4n - 15 = n \ \text{ or } \ 4n-15 = -n\\\\-15 = n-4n \ \text{ or } \ -15 = -n-4n\\\\-15 = -3n \ \text{ or } \ -15 = -5n\\\\-3n = -15 \ \text{ or } \ -5n = -15\\\\n = \frac{-15}{-3} \ \text{ or } \ n = \frac{-15}{-5}\\\\n = 5 \ \text{ or } \ n = 3\\\\

==============================================

Problem 2

<h3>Answers: c = 1 or c = -2/3</h3>

-----------------------

Work Shown:

|2c+8| = |10c|\\\\2c+8 = 10c \ \text{ or } \ 2c+8 = -10c\\\\8 = 10c-2c \ \text{ or } \ 8 = -10c-2c\\\\8 = 8c \ \text{ or } \ 8 = -12c\\\\8c = 8 \ \text{ or } \ -12c = 8\\\\c = \frac{8}{8} \ \text{ or } \ c = \frac{8}{-12}\\\\c = 1 \ \text{ or } \ c = -\frac{2}{3}

8 0
3 years ago
What is the area of the figure​
svp [43]

Formula for the area of a triangle:

( Base X Height ) Divided by 2 or (B×H) ÷ 2

Formula for the area of a circle:

PI times the radius squared or PI × r^2

Area of the triangule part of this figure:

Base: 8ft. Height: 6ft

(8ft × 6ft) ÷ 2

48ft^2 ÷ 2

24ft^2

Since the circular part of the figure is a SEMICIRCLE, we are finding the area of a circle with the same radius but dividing it by 2 since thats just a half of a circle

Area of the semicricle:

Diameter: 10ft,

Therefore the radius is 5ft

(PI x 5ft^2) ÷ 2

39.2699081699 ft^2

39.27 ft^2

Now add these two areas together:

24ft^2 + 38.27ft^2 = 62.27ft^2

Hope it helps

6 0
3 years ago
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