Answer:
−2(3x+12y−5−17x−16y+4)
=(−2)(3x+12y+−5+−17x+−16y+4)
=(−2)(3x)+(−2)(12y)+(−2)(−5)+(−2)(−17x)+(−2)(−16y)+(−2)(4)
=−6x−24y+10+34x+32y−8
=28x+8y+2
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The equation would be y = | x + 1 |.
[(51 + 3) - 3^2] / 9 *2
[(54) - 9] / 9 * 2
[45] /9 * 2
5 * 2
10
remember PEMDAS
Here it is given that f(x)=3x and g(x)=1/x
We have to find the domain of (g o f)(x)
Now it is given that f(x) = 3x
and it is also given that g(x) = 1/x
so (g o f)(x) = g( f(x) ) = g( 3x )
which comes out to be 1 / 3x
The domain of the expression is all the real numbers except where the expression is undefined so the domain of the given expression is all real numbers except 0.