Answer:
Algebra
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How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
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Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
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16x5=80 cause if it bounces 16 times 5 times then
D. 5x+5y=10
The other 3 could be simplified further and have no y value.
Hope that helps
Answer:the answer is
Step-by-step explanation:
First convert 7 1/2 to an improper fraction
15/2 ÷ 3/4
Division of fractions hold the first fraction replaces ÷ with x then flip the second fraction
15/2 x 4/3
Multiply the tops 15x4 =60
Over the bottoms multiplied together 2x3=6
60/6=10
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