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zmey [24]
3 years ago
9

Number 27 pls snsinusnisbihwbhwbihbsyigsyuvwuhbwuhbwhi sorry i have to write 20 characters

Mathematics
1 answer:
Talja [164]3 years ago
8 0
(1, 2.50)
(2, 4.50)
(5, 10.50)
(8, 16.50)
Domain is : 1, 2, 5, 8
Range is : 2.50, 4.50, 10.50, 16.50
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AveGali [126]

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f(x) = x

Step-by-step explanation:

note : slope is positive 1, so the x term must be positive

also note the graph intersects the curve at y = 0, which means that they y-intercept is zero .

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y = mx + b, where m = +1 and b = 0,

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5 0
3 years ago
Solve for A in the equation AB + CD + EFG = Z.
Semenov [28]

Answer:

A =  (Z-CD - EFG)/B

Step-by-step explanation:

AB + CD + EFG = Z.

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AB + CD + EFG-CD -EFG = Z-CD - EFG

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7 0
3 years ago
What is the difference between 8753 and 967?<br>​
evablogger [386]

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7786

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4 0
3 years ago
Read 2 more answers
Fx = 15x - 41x + 14 How do you figure this out?
PSYCHO15rus [73]
Ask a tutor to help
5 0
3 years ago
Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
Mademuasel [1]

Answer:- a.The given expression is equivalent to  \frac{x^{10}y^{14}}{729}



Given expression:- [\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}

=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}

=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}

=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}

=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}

=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}

Thus a. is the right answer.


6 0
3 years ago
Read 2 more answers
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