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rewona [7]
3 years ago
6

I need help with number 16!

Mathematics
1 answer:
Naddik [55]3 years ago
3 0
You do 4,687x2=14061 and then you subtract 14061 by 4052 and that's your answer
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1. 5% of $30 =
stira [4]

Answer:

1 is 1.5

2. is 15

3 is 0.4

4. is 3

5. is 0.8

6 is 10

Step-by-step explanation:

Good luck!

3 0
3 years ago
Which of the binomials below is a factor of this trinomial?<br> x^2+8x+16
vaieri [72.5K]
<h3>Answer:  x+4</h3>

This is because the given expression factors to (x+4)(x+4), which condenses to (x+4)^2.

To factor, think of two numbers that A) multiply to 16, and B) add to 8. Those values would be 4 and 4

4+4 = 8

4*4 = 16

So that's how we end up with (x+4)(x+4). You can use the FOIL rule to expand that out and get x^2+8x+16 again to help verify you have the correct factorization.

5 0
3 years ago
100 POINTS PLZ HELPPP Drag each tile to the correct box. Arrange the expressions in increasing order of their estimated values.
andrew11 [14]

Answer:

<h3>\frac{\sqrt{24}- \sqrt{54} }{\sqrt{6}} = -1   </h3><h3>\sqrt{\frac{9}{20}*\frac{10\sqrt{2} }{3\sqrt{5} } = 1.4142</h3><h3>\frac{10\pi\sqrt{2}-8\pi\sqrt{2}}{2\sqrt{2}}  = π =3.14159</h3><h3>\pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}} = π² = 9.8696</h3>

Explanation:

1.) Rewrite √24 = \sqrt{4*6} = 2\sqrt{6}   Rewrite √54 =\sqrt{9*6}= 3\sqrt{6}

Divide both terms by the denominator; √6 cancels. 2-3 = -1

2.) Rewrite as \frac{3}{2\sqrt{5}} ×\frac{10\sqrt{2}}{3\sqrt{5}}  The 3's cancel.  10/2 = 5√2 in the numerator.

√5 × √5 = 5 in the denominator.  The 5's cancel.

That leaves √2 ≈1.4142

3.) Divide the terms in the numerator by the term in the denominator.

√2's cancel.  10π/2 = 5π   8π/2 = 4π  

Subtract and we are left with π = 3.14159

4.) \pi\sqrt{\frac{5}{3}}\cdot\pi\sqrt{\frac{3}{5}}  The square roots are reciprocals. They multiply to 1

We are left with π × π = π² ≈  9.8696

<h3> </h3>

8 0
3 years ago
Read 2 more answers
Suppose we wish to construct the perpendicular bisector of line segment EF. We can correctly begin by placing the compass point
julia-pushkina [17]
- to a point which is more than halfway to the point F. Then draw an arc  around the point. Next place the compass point at  F and,  keeping the same distance between the points of the compass,  draw another arc so as to intersect the first arc at 2 points above and below the line EF. Finally draw a line passing through these 2 points of intersection.  This is the perpendicular bisector of EF.
3 0
3 years ago
Read 2 more answers
It's #25 guys. Show your work!
Ronch [10]
y+8 = \frac{1}{2}(x-7) is equivalent to <span>y-(-8) = \frac{1}{2}(x-7)

That is in the form </span><span>y-y_{1} = m(x-x_{1}) which is point slope form

In this case,

m = 1/2 is the slope
(x1,y1) = (7,-8) is the point the line goes through</span>
6 0
4 years ago
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