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3 years ago

Combine f(x) =(x)(2x + 5) and g(x) = 2x2 - 13x + 6 Addition

Mathematics

1 answer:

Serggg [28]3 years ago

6 0

Answer:

f(x) + g(x) is 2(2x² - 4x - 3)

Step-by-step explanation:

$f(x) + g(x) = (x)(2x + 5) + ( {2x}^{2} - 13x + 6) \\ = (2 {x}^{2} + 5x) + (2 {x}^{2} - 13x + 6) \\ = 4 {x}^{2} - 8x - 6 \\ = 2(2 {x}^{2} - 4x - 3)$

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kirza4 [7]

Variance is the average of the square of the differences of each data with the mean. To calculate for the variance, we first calculate for the mean. Then, we subtract each data with the mean. Next, each difference would be squared and added. The resulting value would be divided on how many data are used. We calculate as follows:

Mean = 9 + 7 + 6.5 + 7.5 + 7 + 8 + 5 + 6 + 7.5 + 8 / 10
Mean = 6.4

Squared of the sum of the differences = (9-6.4)^2 + (7-6.4)^2 + (6.5-6.4)^2 + (7.5-6.4)^2 + (7-6.4)^2 + (8-6.4)^2 + (5-6.4)^2 + (6-6.4)^2 + (7.5-6.4)^2 + (8-6.4)^2 = 17.15

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4 years ago

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Mumz [18]

Answer:

Minimum value = 43, $Q_1=52$ , $Q_2=Median=61$ , $Q_3=67$ , Maximum value = 69.

Distribution is negative skewed.

Step-by-step explanation:

The given data set is

44, 43, 67, 68, 57, 65, 52, 62, 69, 54, 53, 61, 67, 48, 65

Arrange the data in ascending order

43, 44, 48, 52, 53, 54, 57, 61, 62, 65, 65, 67, 67, 68, 69

Divide the data in 4 equal parts.

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Minimum value = 43

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$Q_2=Median=61$

$Q_3=67$

Maximum value = 69

Starting and end point of box plot represent the minimum and maximum value respectively. Box starts from the first quartile to the third quartile. A vertical line goes through the box at the median.

The shape of the distribution.

Normally distributed: If $Q_3-Q_2=Q_2-Q_1$

Positive skew: If $Q_3-Q_2>Q_2-Q_1$

Negative skew: If $Q_3-Q_2$

For the given data set

$Q_3-Q_2=67-61=6$

$Q_2-Q_1=61-52=9$

Since $Q_3-Q_2$ , therefore the given distribution is negative skewed.

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4 years ago

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kiruha [24]

Answer:

Step-by-step explanation:

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Marizza181 [45]

Answer:

Step-by-step explanation:

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