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timurjin [86]
3 years ago
10

PLEASE HELP ME WITH THIS STATISTICS WORK SAMPLE (will give brainliest)

Mathematics
2 answers:
djyliett [7]3 years ago
6 0
The table shown shows the heights of voices. 
To get the tallest height you calculate the mean of each voice. 
Mean height of soprano;
(60+62+62+64+65+65+66+66+67+68)/10 = 645/10 =64.5
Mean height of alto;
(60+61+62+63+64+65+66+69+70+72)/10 =592/10 =59.2
Mean height of tenor;
(64+66+66+67+68+70+72+73+74+76)/10 = 550/10 =55
mean height of Bass;
(66+68+68+69+70+70+71+72+73+75)/10 = 702/10 =70.2

The two voice parts that have the tallest singers are Soprano and Bass.

These is because the two voices have the highest average height. 

Stella [2.4K]3 years ago
3 0
Hey, this is for your question with the tennisballs and the air between them (i do not use inches here so i'm not really sure about that)

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In T-ball, the distance to each successive base is 50 feet. If the distance from home plate to the pitcher’s mound is 38 feet, h
JulijaS [17]

Answer:

<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>

Step-by-step explanation:

The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.

We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

50^{2} =38^{2}+x^{2}\\x^{2}=50^{2}-38^{2}\\x=\sqrt{2500-1444}\\ x=\sqrt{1056}\\ x \approx 32.5 \ ft

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.

Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

50^{2}=32.5^{2}+y^{2}\\y^{2}=50^{2}-32.5^{2}\\y=\sqrt{2500-1056.25}\\ y =\sqrt{1443} \approx 37.99

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.

<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>

8 0
3 years ago
Solve the absolute value equation. |4x-1|=1
yuradex [85]
.5 because first you add 1 on each side, that gets rid of the 1 on the left. then divide by 4
4 0
3 years ago
Read 2 more answers
The probability of getting a head when a biased coin is tossed is 2/5. The coin is tossed three times. Find the following probab
NeTakaya

Answer:

<u>P(three tails) = 27/125 or 21.6%</u>

<u>P(two tails followed by one head) = 18/125 or 14.4%.</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the questions correctly:

Probability of getting a head when a biased coin is tossed = 2/5

therefore,

Probability of getting a tails when a biased coin is tossed = 3/5

2. Find the following probabilities and select the correct solution.

P(three tails) =

3/5 * 3/5 * 3/5 = 27/125 or 21.6%

P(two tails followed by one head) =

3/5 * 3/5 * 2/5 = 18/125 or 14.4%.

6 0
3 years ago
In the same diagram of the staircase railing, what is the value of n? (Picture included)
BaLLatris [955]
Hello,

Angle BCH and CHJ are alternate-interior ( and have the same measure)

82+30=3n+7
==>3n=105
==>n=35
8 0
3 years ago
Read 2 more answers
Quick I need help!
kkurt [141]
Im not too sure but i would say 27
5 0
3 years ago
Read 2 more answers
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